1 |
4 |
1 |
10 |
7 |
15 |
8 |
15 |
8 |
15 |
Explanation
A's 1 day's work = | 1 | ; |
15 |
B's 1 day's work = | 1 | ; |
20 |
(A + B)'s 1 day's work = | ❨ | 1 | + | 1 | ❩ | = | 7 | . |
15 | 20 | 60 |
(A + B)'s 4 day's work = | ❨ | 7 | x 4 | ❩ | = | 7 | . |
60 | 15 |
Therefore, Remaining work = | ❨ | 1 - | 7 | ❩ | = | 8 | . |
15 | 15 |
4th observation i.e., 8 is the median.
47/10000 = .0047
.02 =(2/100) x 100% =2%
Let N / 11 = 233
Then, N = 233 x 11 = 2563
? Missing digit is 5.
121012 = 12 x 10084 + 4
? remainder = 4
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
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