(A + B)'s 1 day's work = | 1 |
10 |
C's 1 day's work = | 1 |
50 |
(A + B + C)'s 1 day's work = | ❨ | 1 | + | 1 | ❩ | = | 6 | = | 3 | . .... (i) |
10 | 50 | 50 | 25 |
A's 1 day's work = (B + C)'s 1 day's work .... (ii)
From (i) and (ii), we get: 2 x (A's 1 day's work) = | 3 |
25 |
⟹ A's 1 day's work = | 3 | . |
50 |
∴ B's 1 day's work | ❨ | 1 | - | 3 | ❩ | = | 2 | = | 1 | . |
10 | 50 | 50 | 25 |
So, B alone could do the work in 25 days.
S.I. = Rs.(1200*10*1)/100=rs.120
C.I. =rs[1200*(1+5/100)2-1200]=rs.123
Difference = Rs.(123-120) =Rs.3
Sum = (B.D * T.D) / (B.D) -(T.D)
= (120 * 110) / (120 -110)
= 1320
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.