5 | 5 |
11 |
5 | 6 |
11 |
6 | 5 |
11 |
6 | 6 |
11 |
5 | 5 |
11 |
Q can complete the work in (8 x 10) hrs. = 80 hrs.
∴ P's1 hour's work = | 1 | and Q's 1 hour's work = | 1 | . |
96 | 80 |
(P + Q)'s 1 hour's work = | ❨ | 1 | + | 1 | ❩ | = | 11 | . |
96 | 80 | 480 |
So, both P and Q will finish the work in | ❨ | 480 | ❩ | hrs. |
11 |
∴ Number of days of 8 hours each = | ❨ | 480 | x | 1 | ❩ | = | 60 | days = 5 | 5 | days. |
11 | 8 | 11 | 11 |
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
Subtract 20, 25, 30, 35, 40, 45 from successive numbers. So 0 is wrong.
NA
Each previous number is multiplied by 2.
? 8 m shadow means original height = 12 m
? 1 m shadow means original height = 12/8 m
? 100 m shadow means original height = (12/8) x 100 m
= (6/4) x 100 = 6 x 25 = 150 m
Let 8% of 96 = y of 1/25
? (8 x 96)/100 = y/25
? y = (8 x 96 x 25)/100 = 192
Since the principal is not given, so data is inadequate.
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