9 | 1 | days |
5 |
9 | 2 | days |
5 |
9 | 3 | days |
5 |
9 | 3 | days |
5 |
Explanation
(A + B + C)'s 1 day's work = | 1 | , |
4 |
A's 1 day's work = | 1 | , |
16 |
B's 1 day's work = | 1 | . |
12 |
∴ C's 1 day's work = | 1 | - | ❨ | 1 | + | 1 | ❩ | = | ❨ | 1 | - | 7 | ❩ | = | 5 | . |
4 | 16 | 12 | 4 | 48 | 48 |
So, C alone can do the work in | 48 | = 9 | 3 | days. |
5 | 5 |
4th observation i.e., 8 is the median.
47/10000 = .0047
.02 =(2/100) x 100% =2%
Let N / 11 = 233
Then, N = 233 x 11 = 2563
? Missing digit is 5.
121012 = 12 x 10084 + 4
? remainder = 4
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
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