(1/2)x | + | (1/2)x | = 10 |
21 | 24 |
⟹ | x | + | x | = 20 |
21 | 24 |
⟹ 15x = 168 x 20
⟹ x = | ❨ | 168 x 20 | ❩ | = 224 km. |
15 |
Let the length of each train = L metres
Relative speed = (46 - 36) = 10 km/hr. = 10 x (5/18) = 25/9 m/sec
Distance covered in crossing = (L + L) = 2L metres
? 2L x (9/25) = 36
? L = (25 x 36)/(2 x 9) = 50 metres.
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