(1/2)x | + | (1/2)x | = 10 |
21 | 24 |
⟹ | x | + | x | = 20 |
21 | 24 |
⟹ 15x = 168 x 20
⟹ x = | ❨ | 168 x 20 | ❩ | = 224 km. |
15 |
Then, 8x = | ❨ | 400 | ❩ | = 100 |
4 |
⟹ x = | ❨ | 100 | ❩ | = 12.5 |
8 |
∴ Speed of first train = (7 x 12.5) km/hr = 87.5 km/hr.
Then, | x | = | x + 20 |
10 | 14 |
⟹ 14x = 10x + 200
⟹ 4x = 200
⟹ x = 50 km.
Then, | 600 | - | 600 | = 200 |
x | x + (1/2) |
⟹ | 600 | - | 1200 | = 200 |
x | 2x + 1 |
⟹ x(2x + 1) = 3
⟹ 2x2 + x - 3 = 0
⟹ (2x + 3)(x - 1) = 0
⟹ x = 1 hr. [neglecting the -ve value of x]
17 | 6 | km/hr |
7 |
Time taken = 1 hr 40 min 48 sec = 1 hr 40 | 4 | min = 1 | 51 | hrs = | 126 | hrs. |
5 | 75 | 75 |
Let the actual speed be x km/hr.
Then, | 5 | x x | 126 | = 42 |
7 | 75 |
⟹ x = | ❨ | 42 x 7 x 75 | ❩ | = 35 km/hr. |
5 x 126 |
Then, speed of the train = | 150 | x | = | ❨ | 3 | x | ❩kmph. |
100 | 2 |
∴ | 75 | - | 75 | = | 125 |
x | (3/2)x | 10 x 60 |
⟹ | 75 | - | 50 | = | 5 |
x | x | 24 |
⟹ x = | ❨ | 25 x24 | ❩ | = 120 kmph. |
5 |
Speed = Distance/Time
Speed = 1200/(5/3) km/hr. [We can write 1⅔ hours as 5/3 hours]
∴ Required speed = | ❨ | 1200 x | 3 | ❩km/hr | = 720 km/hr. |
5 |
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