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  • Question
  • The value of log2 16 is:


  • Options
  • A.
    1
    8
  • B. 4
  • C. 8
  • D. 16

  • Correct Answer


  • Explanation
    Let log2 16 = n.

    Then, 2n = 16 = 24     ⟹     n = 4.

    ∴ log2 16 = 4.


    Logarithm problems


    Search Results


    • 1. If log10 2 = 0.3010, the value of log10 80 is:

    • Options
    • A. 1.6020
    • B. 1.9030
    • C. 3.9030
    • D. None of these
    • Discuss
    • 2. If log10 2 = 0.3010, then log2 10 is equal to:

    • Options
    • A.
      699
      301
    • B.
      1000
      301
    • C. 0.3010
    • D. 0.6990
    • Discuss
    • 3. If ax = by, then:

    • Options
    • A.
      log a = x
      b y
    • B.
      log a = x
      log b y
    • C.
      log a = y
      log b x
    • D. None of these
    • Discuss
    • 4. 
      If log a + log b = log (a + b), then:
      b a

    • Options
    • A. a + b = 1
    • B. a - b = 1
    • C. a = b
    • D. a2 - b2 = 1
    • Discuss
    • 5. A boat can travel with a speed of 13 km/hr in still water. If the speed of the stream is 4 km/hr, find the time taken by the boat to go 68 km downstream.

    • Options
    • A. 2 hours
    • B. 3 hours
    • C. 4 hours
    • D. 5 hours
    • Discuss
    • 6. If log10 5 + log10 (5x + 1) = log10 (x + 5) + 1, then x is equal to:

    • Options
    • A. 1
    • B. 3
    • C. 5
    • D. 10
    • Discuss
    • 7. Which of the following statements is not correct?

    • Options
    • A. log10 10 = 1
    • B. log (2 + 3) = log (2 x 3)
    • C. log10 1 = 0
    • D. log (1 + 2 + 3) = log 1 + log 2 + log 3
    • Discuss
    • 8. If log 2 = 0.30103, the number of digits in 264 is:

    • Options
    • A. 18
    • B. 19
    • C. 20
    • D. 21
    • Discuss
    • 9. If log 2 = 0.3010 and log 3 = 0.4771, the value of log5 512 is:

    • Options
    • A. 2.870
    • B. 2.967
    • C. 3.876
    • D. 3.912
    • Discuss
    • 10. 
      If log10 7 = a, then log10 1 is equal to:
      70

    • Options
    • A. - (1 + a)
    • B. (1 + a)-1
    • C.
      a
      10
    • D.
      1
      10a
    • Discuss


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