Cost of 1 metre = Rs. | ❨ | d | ❩ |
x |
Cost of y metres = Rs. | ❨ | d | . y | ❩ | = Rs. | ❨ | yd | ❩. |
x | x |
Amount given to A= 9k + 26
Amount given to B = 13k + 28
and amount given to C = 8k + 32
According to the question,
(9k + 26) + (13k + 28) + (8k + 32) = 2186
? 30 k + 86 = 2186
? 30 k = 2100
? k = 70
Hence, amount given to A = 9k + 26 = 9 x 70 + 26
= 630 + 26 = ? 656
Gold in C =(7/9 + 7/18) = 21/18 = 7/6
Copper in C = (2/9 + 11/18) = 15/18 = 5/6
? Gold : Copper = 7/6 : 5/6 = 7 : 5
Work done by (x + 2 ) men in (x - 3) days = (x + 2) (x - 3)
Work done by x men in (x - 2) days = x(x - 2)
? (x + 2) (x - 3) = x(x - 2)
On Solving, we get x = 6
A : B = 11/2 = 3 : 2 = 3 x 7 : 2 x 7 = 21 : 14
B : C = 13/4 : 1 = 7 : 4 = 7 x 2 : 4 x 2 = 14 : 8
? A : B : C = 21 : 14 : 8
? C's share = [8/(21 + 14 + 8)] x 1290 = ? 240
Let the income of two persons are 7k and 3k
Expenditure of first person = 7k - 300
Expenditure of second person = 3k - 300
According to the question,
(7k - 300)/(3k - 300) = 5/2
? 14k - 600 = 15k - 1500
? k = 900
Income of first person = 7k = 7 x 900
= ? 6300
Given that
Sanjay + Suresh = 120 ...(i)
Sanjay - Suresh = 30 ...(ii)
By adding Eqs (I) and (ii) we get
2 x sanjay = 150
? sanjay = 150/2 = 75 kg
? Weight of Suresh = 75 - 35 = 45 kg
? Suresh : Sanjay = 45 : 75 = 3 : 5 = 3/5 = 0.6
Milk = 85 x (27/34) kg = 135/2 kg = 67.5 kg
Water = 85 x (7/34) kg = 35/2 kg = 17.5 kg
Let Amount of water to be added is x,
? 67.5 / (17.5 + x) = 3/1
? 3 (17.5 + x) = 67.5
? x =5
? Water to be added = 5 kg.
1/2A = 1/3B =1/6C = x
? A = 2x, B = 3x, C =6x
? A : B : C = 2 : 3 : 6
Third part = Rs. (1870 x 6/11) = Rs. 1020
let the number of adult men be N.
Then, ratio of the numbers of adult men and adult women
9 : 7 = N : 4.2
? N = (9/7) x 4.2 = 5.4 Lakh
Total adult population = 4.2 + 5.4 = 9.6 lakh.
If the population of the town be M Lakh,
then, 80M/100 = 9.6
? M = (9.6 x 100)/80 = 12 lakh
2A/5 + 40 = 2B/7 + 20 = 9C/17 + 10 = K
Then, A = (5/2) x (K - 40), B = (7/2) x (K - 20), C = (17/9) x (K - 10)
According to the question, A + B + C = 600
? (5/2) x ( K - 40) + (7/2) x (K - 20) + (17/9) x (K - 10) = 600
? 45 x (K - 40 ) + 63 x (K - 20) + 34 x (K - 10) = 10800
? 45K - 1800 + 63K - 1260 + 34K - 340 = 10800
? 142K - 3400 = 10800
? 142K = 10800 + 3400
? 142K = 14200
? K = 14200/142 =100
? B = (7/2) x (K - 20) = (7/2) x (100 - 20)
= (7 x 80)/2 = 7 x 40
= ? 280
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