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- Question
3 pumps, working 8 hours a day, can empty a tank in 2 days. How many hours a day must 4 pumps work to empty the tank in 1 day?
Options- A. 9
- B. 10
- C. 11
- D. 12
- Correct Answer
- 12
Explanation
Let the required number of working hours per day be xMore pumps, Less working hours per day (Indirect Proportion)
Less days, More working hours per day (Indirect Proportion)
Pumps 4 : 3 ] :: 8 : x Days 1 : 2 ∴ 4 x 1 x x = 3 x 2 x 8
⟹ x = (3 x 2 x 8) (4) ⟹ x = 12.
- 1. 36 men can complete a piece of work in 18 days. In how many days will 27 men complete the same work?
Options- A. 12
- B. 18
- C. 22
- D. 24
- E. None of these Discuss
- 2. In a dairy farm, 40 cows eat 40 bags of husk in 40 days. In how many days one cow will eat one bag of husk?
Options- A. 1
- B. 11⁄40
- C. 40
- D. 80 Discuss
- 3.
If x = 3 + 2√2, then the value of ❨ √x - 1 ❩ is: √x
Options- A. 1
- B. 2
- C. 2√2
- D. 3√3 Discuss
- 4. (17)3.5 x (17)? = 178
Options- A. 2.29
- B. 2.75
- C. 4.25
- D. 4.5 Discuss
- 5. (0.04)-1.5 =?
Options- A. 25
- B. 125
- C. 250
- D. 625 Discuss
- 6. 4 mat-weavers can weave 4 mats in 4 days. At the same rate, how many mats would be woven by 8 mat-weavers in 8 days?
Options- A. 4
- B. 8
- C. 12
- D. 16 Discuss
- 7. A flagstaff 17.5 m high casts a shadow of length 40.25 m. The height of the building, which casts a shadow of length 28.75 m under similar conditions will be:
Options- A. 10 m
- B. 12.5 m
- C. 17.5 m
- D. 21.25 m Discuss
- 8. An industrial loom weaves 0.128 metres of cloth every second. Approximately, how many seconds will it take for the loom to weave 25 metres of cloth?
Options- A. 178
- B. 195
- C. 204
- D. 488 Discuss
- 9. If 7 spiders make 7 webs in 7 days, then 1 spider will make 1 web in how many days?
Options- A. 1
- B. 7⁄2
- C. 7
- D. 49 Discuss
- 10. In a camp, there is a meal for 120 men or 200 children. If 150 children have taken the meal, how many men will be catered to with remaining meal?
Options- A. 20
- B. 30
- C. 40
- D. 50 Discuss
Chain Rule problems
Search Results
Correct Answer: 24
Explanation:
Let the required number of days be x
Less men, More days (Indirect Proportion)
∴ 27 : 36 :: 18 : x ⟺ 27 x x = 36 x 18
| ⟹ x = | 36 x 18 |
| 27 |
⟹ x = 24.
Correct Answer: 40
Explanation:
Let the required number of days be x
Less cows, More days (Indirect Proportion)
Less bags, Less days (Direct Proportion)
| Cows | 1 | : | 40 | ] | :: 40 : x |
| Bags | 40 | : | 1 |
∴ 1 x 40 x x = 40 x 1 x 40
⟹ x = 40.
Correct Answer: 2
Explanation:
| ❨ | √x | - | 1 | ❩ | 2 | = x + | 1 | - 2 |
| √x | x |
| = (3 + 2√2) + | 1 | - 2 |
| (3 + 2√2) |
| = (3 + 2√2) + | 1 | x | (3 - 2√2) | - 2 |
| (3 + 2√2) | (3 - 2√2) |
= (3 + 2√2) + (3 - 2√2) - 2
= 4.
| ∴ | ❨ | √x | - | 1 | ❩ | = 2. |
| √x |
Correct Answer: 4.5
Explanation:
Let (17) 3.5 x (17) x = 17 8
Then, (17)3.5 + x = 178.
∴ 3.5 + x = 8
⟹ x = (8 - 3.5)
⟹ x = 4.5
Correct Answer: 125
Explanation:
| (0.04)-1.5 = | ❨ | 4 | ❩ | -1.5 |
| 100 |
| = | ❨ | 1 | ❩ | -(3/2) |
| 25 |
= (25)(3/2)
= (52)(3/2)
= (5)2 x (3/2)
= 53
= 125.
Correct Answer: 16
Explanation:
Let the required number of bottles be x
More weavers, More mats (Direct Proportion)
More days, More mats (Direct Proportion)
| Wavers | 4 | : | 8 | ] | :: 4 : x |
| Days | 4 | : | 8 |
∴ 4 x 4 x x = 8 x 8 x 4
| ⟹ x = | (8 x 8 x 4) |
| (4 x 4) |
⟹ x = 16.
Correct Answer: 12.5 m
Explanation:
Let the height of the building x metres.
Less lengthy shadow, Less in the height (Direct Proportion)
∴ 40.25 : 28.75 :: 17.5 : x ⟺ 40.25 x x = 28.75 x 17.5
| x = | 28.75 x 17.5 |
| 40.25 |
⟹ x = 12.5
Correct Answer: 195
Explanation:
Let the required time be x seconds.
More metres, More time (Direct Proportion)
∴ 0.128 : 25 :: 1 : x ⟺ 0.128x = 25 x 1
| x = | 25 | = | 25 x 1000 |
| 0.128 | 128 |
⟹ x = 195.31.
∴ Required time = 195 sec (approximately).
Correct Answer: 7
Explanation:
Let the required number days be x
Less spiders, More days (Indirect Proportion)
Less webs, Less days (Direct Proportion)
| Spiders | 1 | : | 7 | ] | :: 7 : x |
| Webs | 7 | : | 1 |
∴ 1 x 7 x x = 7 x 1 x 7
⟹ x = 7.
Correct Answer: 30
Explanation:
There is a meal for 200 children. 150 children have taken the meal.
Remaining meal is to be catered to 50 children.
Now, 200 children ≡ 120 men.
| 50 children ≡ | ❨ | 120 | x 50 | ❩ | = 30 men. |
| 200 |
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