Then, the capacity of tank = 25x.
New capacity of bucket = | 2 | x |
5 |
∴ Required number of buckets = | 25x |
(2x/5) |
= | ❨ 25x | x | 5 | ❩ |
2x |
= | 125 |
2 |
= 62.5
Then, x + y = 48 .... (i)
and 2x + 4y = 140 ⟹ x + 2y = 70 .... (ii)
Solving (i) and (ii) we get: x = 26, y = 22.
∴ The required answer = 26.
Now, working hours in 4 weeks = (5 x 8 x 4) = 160.
∴ 160 x 2.40 + x x 3.20 = 432
⟹ 3.20x = 432 - 384 = 48
⟹ x = 15.
Hence, total hours of work = (160 + 15) = 175.
Then, x x | 1 | x = | x | x 16 ⟺ x = 64. |
8 | 2 |
∴ Number of notebooks = | 1 | x2 = | ❨ | 1 | x 64 x 64 | ❩ | = 512. |
8 | 8 |
Original share of 1 person = | 1 |
8 |
New share of 1 person = | 1 |
7 |
Increase = | ❨ | 1 | - | 1 | ❩ | = | 1 |
7 | 8 | 56 |
∴ Required fraction = | (1/56) | = | ❨ | 1 | x | 8 | ❩ | = | 1 |
(1/8) | 56 | 1 | 7 |
Then, 10x = 4y or y = | 5 | x. |
2 |
∴ 15x + 2y = 4000
⟹ 15x + 2 x | 5 | x = 4000 |
2 |
⟹ 20x = 4000
∴ x = 200.
So, y = | ❨ | 5 | x 200 | ❩ | = 500. |
2 |
Hence, the cost of 12 chairs and 3 tables = 12x + 3y
= Rs. (2400 + 1500)
= Rs. 3900.
Then, 2x + 4y = 1600 .... (i)
and x + 6y = 1600 .... (ii)
Divide equation (i) by 2, we get the below equation. => x + 2y = 800. --- (iii) Now subtract (iii) from (ii) x + 6y = 1600 (-) x + 2y = 800 ---------------- 4y = 800 ---------------- Therefore, y = 200. Now apply value of y in (iii) => x + 2 x 200 = 800 => x + 400 = 800 Therefore x = 400
Solving (i) and (ii) we get x = 400, y = 200.
∴ Cost of 12 shirts = Rs. (12 x 200) = Rs. 2400.
Then, B's share = Rs. | x | , A's share = Rs. | ❨ | 2 | x | x | ❩ | = Rs. | x |
4 | 3 | 4 | 6 |
∴ | x | + | x | + x = 1360 |
6 | 4 |
⟹ | 17x | = 1360 |
12 |
⟹ x = | 1360 x 12 | = Rs. 960 |
17 |
Hence, B's share = Rs. | ❨ | 960 | ❩ | = Rs. 240. |
4 |
3x + y = 243 = 35 ⟺ x + y = 5 ....(ii)
On solving (i) and (ii), we get x = 4.
Then, | (52)7.5 x (5)2.5 | = 5x |
(53)1.5 |
⟹ | 5(2 x 7.5) x 52.5 | = 5x |
5(3 x 1.5) |
⟹ | 515 x 52.5 | = 5x |
54.5 |
⟹ 5x = 5(15 + 2.5 - 4.5)
⟹ 5x = 513
∴ x = 13.
❨ | xb | ❩ | (b + c - a) | . | ❨ | xc | ❩ | (c + a - b) | . | ❨ | xa | ❩ | (a + b - c) | =? |
xc | xa | xb |
Given Exp. |
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