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- Question
A man has some hens and cows. If the number of heads be 48 and the number of feet equals 140, then the number of hens will be:
Options- A. 22
- B. 23
- C. 24
- D. 26
- Correct Answer
- 26
Explanation
Let the number of hens be x and the number of cows be yThen, x + y = 48 .... (i)
and 2x + 4y = 140 ⟹ x + 2y = 70 .... (ii)
Solving (i) and (ii) we get: x = 26, y = 22.
∴ The required answer = 26.
- 1. The number of digits in the numeral for (875) 16?
Options- A. 47 digit
- B. 48 digit
- C. 49 digit
- D. 50 digit Discuss
- 2. The population of a town at the beginning of the year 1986 was 2,65,000. If the rate of increase be 52 per thousand of the population. Find the population at the beginning of the year 1991.?
Options- A. 3,40,400
- B. 3,41,400
- C. 3,42,400
- D. 3,43,400 Discuss
- 3. What rate per cent per annum compound interest will Rs. 3,000 in 3 years if the interest is reckoned half yearly?
Options- A. 12%
- B. 13%
- C. 14%
- D. 15% Discuss
- 4. In a lottery there are 20 prizes and 15 blanks. What is the probability of getting prize?
Options- A. 1/10
- B. 2/5
- C. 4/7
- D. 2/7 Discuss
- 5. A number is chosen at random among the first 120 natural numbers. The probability of the number chosen being a multiple of 5 or 15 is?
Options- A. 1/5
- B. 1/8
- C. 1/6
- D. None of these Discuss
- 6. A single letter is selected at random from the word 'PROBABILITY' . The probability that it is a vowel, is?
Options- A. 3/11
- B. 4/11
- C. 2/11
- D. 0 Discuss
- 7. Ticket numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn bears a number which is a multiple of 3 or 7?
Options- A. 1/15
- B. 1/2
- C. 2/5
- D. 7/20 Discuss
- 8. The odds against the occurrence of an event are 5 : 4. The probability of its occurrence is?
Options- A. 4/5
- B. 4/9
- C. 1/5
- D. 1/4 Discuss
- 9. A bag contains 8 red and 5 white balls. 2 balls are drawn at random. What is the probability that both are white?
Options- A. 5/16
- B. 2/13
- C. 3/26
- D. 5/39 Discuss
- 10. Three unbiased coins are tossed. What is the probability of getting at most 2 heads?
Options- A. 1/4
- B. 3/8
- C. 7/8
- D. 1/2 Discuss
More questions
Correct Answer: 48 digit
Explanation:
? N = (875)16
? log N = log (875)16
? log N = 16 log (875)
= 16 x (2.942)
= 47.072
? No.of digits = 47 + 1 = 48
Correct Answer: 3,41,400
Explanation:
We have r = Rate of increase
= 52/1000 x 100
= 5.2, n = 5, P0 = 265000
? P = 265000(1 + 5.2 / 100)5
? log P = log 265000 + 5(log 105.2 - log 100)
= 5.4232 + 5(2.0220 - 2)
= 5.4232 + 0.1100
= 5.5332
? P = antilog(5.5332) = 341400
Correct Answer: 14%
Explanation:
? 3000 = 2000(1 + r/200)6
? 3/2 = (1 + r/200)6
? 1 + r/200 = (3/2)1/6
? log(1 + r/200)= 1/6(log 3 - log 2 )
? log(1 + r/200)= 1/6(0.4771-.3010)
= 0.02935
? (1 + r/200) = antilog(.02935)
? 1 + r/200 = 1.070 = 1 + 7/100
? r = 14%
Correct Answer: 4/7
Explanation:
P (getting a prize ) = 20 / (20 + 15 ) = 20 / 35 = 4/7
Correct Answer: 1/5
Explanation:
? Total no. of favourable cases i,e., (5, 10, 15, 20, 25, 30, ....., 105, 110, 115, 120) = 24.
? Reqd . Prob = 24/120 = 1/5
Correct Answer: 4/11
Explanation:
Total number of letters = n(S) = 11
whereas, number of vowels = n(E) = 4
? Required probability = n(E)/n(s) = 4/11
Correct Answer: 2/5
Explanation:
Clearly, n(S) = 20 and E = { 3, 6, 9, 12, 15, 18, 7, 14 } i.e., n(E) = 8
? P(E) = n(E)/ n(S) = 8/20 = 2/5
Correct Answer: 4/9
Explanation:
Number of cases favourable of E = 4
Total Number of cases = (5 + 4 ) = 9
? P(E) = 4/9
Correct Answer: 5/39
Explanation:
n(S) = Number of ways of drawing 2 balls out of 13 = 13C2 = 13 x 12 / 2= 78
n(E) = No. of ways of drawing 2 balls out of 5 = 5C2 = 5 x 4 / 2 = 10
? P(E) = n(E)/n(S) = 10/78 = 5/39
Correct Answer: 7/8
Explanation:
? n(S) = (2)3 = 8
E = Event of getting 0, or 1 or 2 heads
= {TTT, TTH, THT, HTT, HHT, HTH, THH}
? n(E) = 7
? P(E) = n(E)/n(S) = 7/8
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