Other number = | ❨ | 11 x 7700 | ❩ | = 308. |
275 |
= H.C.F. of 1651 and 2032 = 127.
∴ Larger number = (23 x 14) = 322.
101 = 1 x 101
176 = 1 x 2 x 2 x 2 x 2 x 11
182 = 1 x 2 x 7 x 13
So, divisors of 99 are 1, 3, 9, 11, 33, .99
Divisors of 101 are 1 and 101
Divisors of 176 are 1, 2, 4, 8, 11, 16, 22, 44, 88 and 176
Divisors of 182 are 1, 2, 7, 13, 14, 26, 91 and 182.
Hence, 176 has the most number of divisors.
= 540 + 8
= 548.
7 | = | 70 | ; | 13 | = | 65 | ; | 31 | = | 62 |
8 | 80 | 16 | 80 | 40 | 80 |
Since, | 70 | > | 65 | > | 63 | > | 62 | , so | 7 | > | 13 | > | 63 | > | 31 |
80 | 80 | 80 | 80 | 8 | 16 | 80 | 40 |
So, | 7 | is the largest. |
8 |
(469 + 174)2 - (469 - 174)2 | =? |
(469 x 174) |
Given exp. = | (a + b)2 - (a - b)2 |
ab |
= | 4ab |
ab |
= 4 (where a = 469, b = 174.)
Then x + 5x + 10x = 480
⟹ 16x = 480
∴ x = 30.
Hence, total number of notes = 3x = 90.
Then, x - 10 = y + 10 ⟹ x - y = 20 .... (i)
and x + 20 = 2(y - 20) ⟹ x - 2y = -60 .... (ii)
Solving (i) and (ii) we get: x = 100 , y = 80.
∴ The required answer A = 100.
Then, 11 + 57x = 51 - 63x ⟺ 120x = 40
x = | 1 |
3 |
Number of floors covered by David in (1/3) min. = | ❨ | 1 | x 57 | ❩ | = 19. |
3 |
So, their paths cross at (11 +19) i.e., 30th floor.
Shots fired by A = | 5 | x |
8 |
Shots fired by B = | 3 | x |
8 |
Killing shots by A = | 1 | of | 5 | x | = | 5 | x |
3 | 8 | 24 |
Shots missed by B = | 1 | of | 3 | x | = | 3 | x |
2 | 8 | 16 |
∴ | 3x | = 27 or x = | ❨ | 27 x 16 | ❩ | = 144. |
16 | 3 |
Birds killed by A = | 5x | = | ❨ | 5 | x 144 | ❩ | = 30. |
24 | 24 |
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