101 = 1 x 101
176 = 1 x 2 x 2 x 2 x 2 x 11
182 = 1 x 2 x 7 x 13
So, divisors of 99 are 1, 3, 9, 11, 33, .99
Divisors of 101 are 1 and 101
Divisors of 176 are 1, 2, 4, 8, 11, 16, 22, 44, 88 and 176
Divisors of 182 are 1, 2, 7, 13, 14, 26, 91 and 182.
Hence, 176 has the most number of divisors.
Ratio of Speed = 2 : 3 : 4
Ratio of time taken = (1/2) : (1/3) : (1/4) = 6 : 4 : 3
Clearly, If 60 % is equally divided then remaining 40% of total profit will be divided between 2 persons A and B in ratio of (profit of A) : (profit of B)= 12,500 : 8500 = 125 : 85 = 25:17
now difference in amount = 25-17 = 8 this difference = 240
therefore 40% of total profit = 240*(25+17)/(25-17) = 1260
? 100% profit = 1260 / 40 × 100 = 3150
Given 30% of 500
Hence, 30% of Rs. 500 = Rs. 150.
Here, A : B = 2 : 3, B : C = 5 : 7 and C : D = 3 : 10
? A/D = (A/B) x (B/C) x (C/D)
= (2/3) x (5/7) x (3/10)
= 1/7
? A : D = 1 : 7
and
x = 4 and y = 6
x-y = -2
Given, P/Q = 7/5
? (5P - 2Q) / (3P + 2Q) = (5 x 7 - 2 x 5) / (3 x 7 + 2 x 5)
= (35 - 10) / (21 + 10)
= 25/31
Let the number be 'x'
Then, according to the given data,
=
= 84%
Let the numbers be p & q
q-p/4 = 4q/6
=> q-4q/6 = p/4
=> 2q/6 = p/4
=> p/q = 4/3
Let 'M' be the maximum marks in the examination.
Therefore, Madhu got 32% of M = 32M/100 = 0.32M
And Kumar got 42% of M = 42M/100 = 0.42M.
In terms of the maximum marks Kumar got 0.42M - 0.32M = 0.1M more than Madhu. ---- (1)
The problem however, states that Kumar got 16 marks more than the cut-off mark and Madhu got 8 marks less than the cut-off mark. Therefore, Kumar has got 16 + 8 = 24 marks more than Madhu. ---- (2)
Now, Equating (1) and (2), we get
0.1M = 24 => M = 24/0.1 = 240
'M' is the maximum mark and is equal to 240 marks.
We know that Madhu got 32% of the maximum marks.
Therefore, Madhu got 32 x 240/100 = 76.8 marks.
We also know that Madhu got 8 marks less than the cut-off marks.
Therefore, the cut-off marks will be 8 marks more than what Madhu got
= 76.8 + 8 = 84.8.
This can be solved as
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