Then, their L.C.M. = 6x.
So, 6x = 48 or x = 8.
∴ The numbers are 16 and 24.
Hence, required sum = (16 + 24) = 40.
L.C.M. of 15, 25, 40 and 75 is 600.
On dividing 9999 by 600, the remainder is 399.
∴ Required number (9999 - 399) = 9600.
∴ H.C.F. of given numbers = 0.18.
= H.C.F. of 48, 92 and 140 = 4.
84 = 22 x 3 x 7
∴ H.C.F. = 22 x 3 = 12.
On dividing 2497 by 60, the remainder is 37.
∴ Number to be added = (60 - 37) = 23.
So, the numbers 12 and 16.
L.C.M. of 12 and 16 = 48.
2 | 24 - 36 - 40 -------------------- 2 | 12 - 18 - 20 -------------------- 2 | 6 - 9 - 10 ------------------- 3 | 3 - 9 - 5 ------------------- | 1 - 3 - 5 L.C.M. = 2 x 2 x 2 x 3 x 3 x 5 = 360.
= 1008 + 7
= 1015
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