logo

CuriousTab

CuriousTab

Discussion


Home Aptitude Numbers Comments

  • Question
  • The smallest prime number is:


  • Options
  • A. 1
  • B. 2
  • C. 3
  • D. 4

  • Correct Answer


  • Explanation
    The smallest prime number is 2.

  • Numbers problems


    Search Results


    • 1. If x and y are positive integers such that (3x + 7y) is a multiple of 11, then which of the following will be divisible by 11?

    • Options
    • A. 4x + 6y
    • B. x + y + 4
    • C. 9x + 4y
    • D. 4x - 9y
    • Discuss
    • 2. On dividing 2272 as well as 875 by 3-digit number N, we get the same remainder. The sum of the digits of N is:

    • Options
    • A. 10
    • B. 11
    • C. 12
    • D. 13
    • Discuss
    • 3. 287 x 287 + 269 x 269 - 2 x 287 x 269 =?

    • Options
    • A. 534
    • B. 446
    • C. 354
    • D. 324
    • E. None of these
    • Discuss
    • 4. A number when divide by 6 leaves a remainder 3. When the square of the number is divided by 6, the remainder is:

    • Options
    • A. 0 
    • B. 1
    • C. 2
    • D. 3
    • Discuss
    • 5. 8597 -? = 7429 - 4358

    • Options
    • A. 5426
    • B. 5706
    • C. 5526
    • D. 5476
    • E. None of these
    • Discuss
    • 6. 9548 + 7314 = 8362 + (?)

    • Options
    • A. 8230
    • B. 8410
    • C. 8500
    • D. 8600
    • E. None of these
    • Discuss
    • 7. Which of the following numbers will completely divide (461 + 462 + 463 + 464)?

    • Options
    • A. 3
    • B. 10
    • C. 11
    • D. 13
    • Discuss
    • 8. The sum of how many terms of the series 6 + 12 + 18 + 24 + ... is 1800?

    • Options
    • A. 16
    • B. 24
    • C. 20
    • D. 18
    • E. 22
    • Discuss
    • 9. 666 / 6 / 3 =?

    • Options
    • A. 37
    • B. 333
    • C. 111
    • D. 84
    • E. None of these
    • Discuss
    • 10. Which one of the following numbers is completely divisible by 99?

    • Options
    • A. 3572404
    • B. 135792
    • C. 913464
    • D. 114345
    • E. None of these
    • Discuss


    Comments

    There are no comments.

Enter a new Comment