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- Question
A number when divide by 6 leaves a remainder 3. When the square of the number is divided by 6, the remainder is:
Options- A. 0
- B. 1
- C. 2
- D. 3
- Correct Answer
- 3
Explanation
Let x = 6 q + 3.Then, x2 = (6q + 3)2
= 36q2 + 36q + 9
= 6(6q2 + 6q + 1) + 3
Thus, when x2 is divided by 6, then remainder = 3.
- 1. 8597 -? = 7429 - 4358
Options- A. 5426
- B. 5706
- C. 5526
- D. 5476
- E. None of these Discuss
- 2. (12 + 22 + 32 + ... + 102) =?
Options- A. 330
- B. 345
- C. 365
- D. 385 Discuss
- 3. 35 + 15 x 1.5 =?
Options- A. 85
- B. 51.5
- C. 57.5
- D. 5.25
- E. None of these Discuss
- 4. On dividing a number by 5, we get 3 as remainder. What will the remainder when the square of the this number is divided by 5?
Options- A. 0
- B. 1
- C. 2
- D. 4 Discuss
- 5. If the number 5 * 2 is divisible by 6, then * =?
Options- A. 2
- B. 3
- C. 6
- D. 7 Discuss
- 6. 287 x 287 + 269 x 269 - 2 x 287 x 269 =?
Options- A. 534
- B. 446
- C. 354
- D. 324
- E. None of these Discuss
- 7. On dividing 2272 as well as 875 by 3-digit number N, we get the same remainder. The sum of the digits of N is:
Options- A. 10
- B. 11
- C. 12
- D. 13 Discuss
- 8. If x and y are positive integers such that (3x + 7y) is a multiple of 11, then which of the following will be divisible by 11?
Options- A. 4x + 6y
- B. x + y + 4
- C. 9x + 4y
- D. 4x - 9y Discuss
- 9. The smallest prime number is:
Options- A. 1
- B. 2
- C. 3
- D. 4 Discuss
- 10. 9548 + 7314 = 8362 + (?)
Options- A. 8230
- B. 8410
- C. 8500
- D. 8600
- E. None of these Discuss
Numbers problems
Search Results
Correct Answer: 5526
Explanation:
7429 Let 8597 - x = 3071 -4358 Then, x = 8597 - 3071 ---- = 5526 3071 ----
Correct Answer: 385
Explanation:
| We know that (12 + 22 + 32 + ... + n2) = | 1 | n(n + 1)(2n + 1) |
| 6 |
| Putting n = 10, required sum = | ❨ | 1 | x 10 x 11 x 21 | ❩ | = 385 |
| 6 |
Correct Answer: 57.5
Explanation:
| Given Exp. = 35 + 15 x | 3 | = 35 + | 45 | = 35 + 22.5 = 57.5 |
| 2 | 2 |
Correct Answer: 4
Explanation:
Let the number be x and on dividing x by 5, we get k as quotient and 3 as remainder.
∴ x = 5k + 3
⟹ x2 = (5k + 3)2
= (25k2 + 30k + 9)
= 5(5k2 + 6k + 1) + 4
∴On dividing x2 by 5, we get 4 as remainder.
Correct Answer: 2
Explanation:
6 = 3 x 2. Clearly, 5 * 2 is divisible by 2. Replace * by x
Then, (5 + x + 2) must be divisible by 3. So, x = 2.
Correct Answer: 324
Explanation:
| Given Exp. | = a2 + b2 - 2ab, where a = 287 and b = 269 |
| = (a - b)2 = (287 - 269)2 | |
| = (182) | |
| = 324 |
Correct Answer: 10
Explanation:
Clearly, (2272 - 875) = 1397, is exactly divisible by N.
Now, 1397 = 11 x 127
∴ The required 3-digit number is 127, the sum of whose digits is 10.
Correct Answer: 4x - 9y
Explanation:
By hit and trial, we put x = 5 and y = 1 so that (3 x + 7 y ) = (3 x 5 + 7 x 1) = 22, which is divisible by 11.
∴ (4x + 6y) = ( 4 x 5 + 6 x 1) = 26, which is not divisible by 11;
(x + y + 4 ) = (5 + 1 + 4) = 10, which is not divisible by 11;
(9x + 4y) = (9 x 5 + 4 x 1) = 49, which is not divisible by 11;
(4x - 9y) = (4 x 5 - 9 x 1) = 11, which is divisible by 11.
Correct Answer: 2
Explanation:
The smallest prime number is 2.
Correct Answer: 8500
Explanation:
9548 16862 = 8362 + x + 7314 x = 16862 - 8362 ----- = 8500 16862 -----
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