∴ | a + b | = | 12 | ⟹ | ❨ | 1 | + | 1 | ❩ | = | 12 |
ab | 35 | b | a | 35 |
∴ Sum of reciprocals of given numbers = | 12 |
35 |
1400 x x = 1050 ⟹ x = | 1050 | = | 3 |
1400 | 4 |
Unit digit must be 0 or 5 and sum of digits must be divisible by 9.
Among given numbers, such number is 202860.
4 a 3 | 9 8 4 } ==> a + 8 = b ==> b - a = 8 13 b 7 |Also, 13 b 7 is divisible by 11 ⟹ (7 + 3) - ( b + 1) = (9 - b )
⟹ (9 - b) = 0
⟹ b = 9
∴ (b = 9 and a = 1) ⟹ (a + b) = 10.
Then, x = 7589 - 3434 = 4155
Then x, = 4300731 - 2535618 = 1765113
854 x 854 x 854 - 276 x 276 x 276 | =? |
854 x 854 + 854 x 276 + 276 x 276 |
Given Exp. = | (a3 - b3) | = (a - b) = (854 - 276) = 578 |
(a2 + ab + b2) |
This is an A.P. in which a = 1, d = 1, n = 45 and l = 45
∴Sn = | n | (a + l) | = | 45 | x (1 + 45) = (45 x 23) = 1035 |
2 | 2 |
Required sum = 1035.
Thus, when 2n is divided by 4, the remainder is 2.
=Unit digit in { 292915317923361 x 17114769 }
= (1 x 9) = 9
This is an A.P. in which a = 102, d = 6 and l = 996
Let the number of terms be n. Then tn = 996.
∴ a + (n - 1)d = 996
⟹ 102 + (n - 1) x 6 = 996
⟹ 6 x (n - 1) = 894
⟹ (n - 1) = 149
⟹ n = 150
∴ Number of terms = 150.
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