So, the required number must be divisible by each one of 3, 7, 47
553681 → (Sum of digits = 28, not divisible by 3)
555181 → (Sum of digits = 25, not divisible by 3)
555681 is divisible by 3, 7, 47.
? = 22.5% of 1350 + 135 % of 225
= (1350 x 225)/100 + (225 x 135)/100
= 303.75 + 303.75 = 607.5 ? 610
Since, 3 women + 18 children complete work in 2 days. Therefore, (3 x 2) women + (18 x 2) children complete work in 1 days i.e, 6 women + 36 children complete work in 1 day.
Work of 36 children for 1 day = 1 - (1/3) = 2/3
[? work of 6 women for 1 day = 1/3]
? 36 children do 2/3 part of the work in 1 day.
36 children can do the work in 3/2 days.
9 children can do the the work in (3/2) x 4 = 6 days
Required no. of words = 12P4 x 4P3
= 12 x 11 x 10 x 9 x 4 x 3 x 2
= 120(100 - 1) x 24
= 288000 - 2880
= 285120
12 persons can be seated around a round table in 11! ways. The total number of ways in which 2 particular persons sit side by side = 10! x 2!.
Hence, the required number of arrangements = 11! - 10! x 2! = 9 x (10!)
Speed in m/sec = 36km/hr x (5/18) = 10 m/sec
Given, Time taken by train to cross the platform = 2 min = 120 sec
Therefore, the distance covered by train in crossing the platform = 10 m/sec x 120 sec = 1200 m
Now, distance covered by train in crossing the platform = Length of train + Length of Platform
Given, Length of train = Length of Platform = x
Therefore, 2x = 1200
so, x = Length of train = 1200/2 = 600 m
? = (15.96)2 + 75 % of 285
? (16)2 + 214 = 256 + 214 = 470
Required number = (L . C . M of 21, 28, 36, 45 ) + 3
= (1260 + 3 )
= 1263
The banker's gain on a certain sum due 1 | 1 | years hence is | 3 | of the banker's |
2 | 25 |
discount. The rate percent is:
5 | 1 | % |
5 |
9 | 1 | % |
11 |
8 | 1 | % |
8 |
6 | 1 | % |
6 |
9 | 1 | % |
11 |
Then, B.G. = Re. | 3 | . |
25 |
∴ T.D. = (B.D. - B.G.) = Re. | ❨ | 1 - | 3 | ❩ | = Re. | 22 | . |
25 | 25 |
Sum = | ❨ | 1 x (22/25) | ❩ | = Rs. | 22 | . |
1-(22/25) | 3 |
S.I. on Rs. | 22 | for 1 | 1 | years is Re. 1. |
3 | 2 |
∴ Rate = | ❨ | 100 x 1 | ❩% |
|
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Total number of marbles = 6 + 4 + 2 + 3 = 15
Ways of selection of two red marbles = n(E) = 6C2
Ways of selection of two marbles = n(S) = 15C2
So, required probability = (6C2) / (15C2)
= (6 x 5) / (15 x 14) = 1/7
4 | A | = | 2 | B | |
15 | 5 |
⟹ A = | ❨ | 2 | x | 15 | ❩B |
5 | 4 |
⟹ A = | 3 | B |
2 |
⟹ | A | = | 3 |
B | 2 |
⟹ A : B = 3 : 2.
∴ B's share = Rs. | ❨ | 1210 x | 2 | ❩ | = Rs. 484. |
5 |
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