Given Exp. | = (397)2 + (104)2 + 2 x 397 x 104 |
= (397 + 104)2 | |
= (501)2 = (500 + 1)2 | |
= (5002) + (1)2 + (2 x 500 x 1) | |
= 250000 + 1 + 1000 | |
= 251001 |
∴ x = 7.
Since 653xy is divisible by 2 and 5 both, so y = 0.
Now, 653x is divisible by 8, so 13x should be divisible by 8.
This happens when x = 6.
∴x + y = (6 + 0) = 6.
19657 Let x - 53651 = 9999 33994 Then, x = 9999 + 53651 = 63650 ----- 53651 -----
2079 is divisible by each of 3, 7, 9, 11.
Given Exp. = | (12)3 x 64 | = | (12)3 x 64 | = (12)2 x 62 = (72)2 = 5184 |
432 | 12 x 62 |
The minimum value of x for which 73x for which 73x is divisible by 8 is, x = 6.
Sum of digits in 425736 = (4 + 2 + 5 + 7 + 3 + 6) = 27, which is divisible by 9.
∴Required value of * is 6.
1904 x 1904 | = (1904)2 |
= (1900 + 4)2 | |
= (1900)2 + (4)2 + (2 x 1900 x 4) | |
= 3610000 + 16 + 15200. | |
= 3625216. |
This is a G.P. in which a = 2, r = | 22 | = 2 and n = 9. |
2 |
∴Sn = | a(rn - 1) | = | 2 x (29 - 1) | = 2 x (512 - 1) = 2 x 511 = 1022. |
(r - 1) | (2 - 1) |
(217)2 + (183)2 | = (200 + 17)2 + (200 - 17)2 |
= 2 x [(200)2 + (17)2] [Ref: (a + b)2 + (a - b)2 = 2(a2 + b2)] | |
= 2[40000 + 289] | |
= 2 x 40289 | |
= 80578. |
∴(6767 + 1) will be divisible by (67 + 1)
∴(6767 + 1) + 66, when divided by 68 will give 66 as remainder.
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.