∴ x = 3, as 632 is divisible 8.
4 | x z = 6 x 1 + 4 = 10 ----------- 5 | y -2 y = 5 x z + 3 = 5 x 10 + 3 = 53 ----------- 6 | z - 3 x = 4 x y + 2 = 4 x 53 + 2 = 214 ----------- | 1 - 4 Hence, required number = 214.
753 x 753 + 247 x 247 - 753 x 247 | =? |
753 x 753 x 753 + 247 x 247 x 247 |
Given Exp. = | (a2 + b2 - ab) | = | 1 | = | 1 | = | 1 |
(a3 + b3) | (a + b) | (753 + 247) | 1000 |
935421 x 625 = 935421 x 54 = 935421 x | ❨ | 10 | ❩ | 4 |
2 |
= | 935421 x 104 | = | 9354210000 |
24 | 16 |
= 584638125
4 | x y = (5 x 1 + 4) = 9 -------- 5 | y -1 x = (4 x y + 1) = (4 x 9 + 1) = 37 -------- | 1 -4 Now, 37 when divided successively by 5 and 4, we get 5 | 37 --------- 4 | 7 - 2 --------- | 1 - 3 Respective remainders are 2 and 3.
Given Exp. = | (12)3 x 64 | = | (12)3 x 64 | = (12)2 x 62 = (72)2 = 5184 |
432 | 12 x 62 |
2079 is divisible by each of 3, 7, 9, 11.
19657 Let x - 53651 = 9999 33994 Then, x = 9999 + 53651 = 63650 ----- 53651 -----
Since 653xy is divisible by 2 and 5 both, so y = 0.
Now, 653x is divisible by 8, so 13x should be divisible by 8.
This happens when x = 6.
∴x + y = (6 + 0) = 6.
∴ x = 7.
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