= (37 x 8q + 37 x 2) + 1
= 37 (8q + 2) + 1
Thus, when the number is divided by 37, the remainder is 1.
47619 x 7 = 333333.
Let the number of terms be n. Then,
a + (n - 1)d = 30
⟹ 2 + (n - 1) x 2 = 30
⟹ n = 15.
∴Sn = | n | (a + l) | = | 15 | x (2 + 30) = (15 x 16) = 240. |
2 | 2 |
Largest 5-digit number = 99999 91) 99999 (1098 91 --- 899 819 ---- 809 728 --- 81 --- Required number = (99999 - 81) = 99918.
∴ 13p + 11 = 17q + 9
⟹ 17q - 13p = 2
⟹ q = | 2 + 13p |
17 |
The least value of p for which q = | 2 + 13p | is a whole number is p = 26 |
17 |
∴ x = (13 x 26 + 11)
= (338 + 11)
= 349
(2n + 2)2 = (2n + 2 + 2n)(2n + 2 - 2n)
= 2(4n + 2)
= 4(2n + 1), which is divisible by 4.
4 | x y = (5 x 1 + 4) = 9 -------- 5 | y -1 x = (4 x y + 1) = (4 x 9 + 1) = 37 -------- | 1 -4 Now, 37 when divided successively by 5 and 4, we get 5 | 37 --------- 4 | 7 - 2 --------- | 1 - 3 Respective remainders are 2 and 3.
935421 x 625 = 935421 x 54 = 935421 x | ❨ | 10 | ❩ | 4 |
2 |
= | 935421 x 104 | = | 9354210000 |
24 | 16 |
= 584638125
753 x 753 + 247 x 247 - 753 x 247 | =? |
753 x 753 x 753 + 247 x 247 x 247 |
Given Exp. = | (a2 + b2 - ab) | = | 1 | = | 1 | = | 1 |
(a3 + b3) | (a + b) | (753 + 247) | 1000 |
4 | x z = 6 x 1 + 4 = 10 ----------- 5 | y -2 y = 5 x z + 3 = 5 x 10 + 3 = 53 ----------- 6 | z - 3 x = 4 x y + 2 = 4 x 53 + 2 = 214 ----------- | 1 - 4 Hence, required number = 214.
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