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  • Question
  • {(476 + 424)2 - 4 x 476 x 424} =?


  • Options
  • A. 2906
  • B. 3116
  • C. 2704
  • D. 2904
  • E. None of these

  • Correct Answer
  • 2704 

    Explanation
    Given Exp. = [(a + b)2 - 4ab], where a = 476 and b = 424
    = [(476 + 424)2 - 4 x 476 x 424]
    = [(900)2 - 807296]
    = 810000 - 807296
    = 2704.

  • Numbers problems


    Search Results


    • 1. 1397 x 1397 =?

    • Options
    • A. 1951609
    • B. 1981709
    • C. 18362619
    • D. 2031719
    • E. None of these
    • Discuss
    • 2. The difference of two numbers is 1365. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder. What is the smaller number?

    • Options
    • A. 240
    • B. 270
    • C. 295
    • D. 360
    • Discuss
    • 3. 5358 x 51 =?

    • Options
    • A. 273258
    • B. 273268
    • C. 273348
    • D. 273358
    • Discuss
    • 4. 8988 ÷ 8 ÷ 4 =?

    • Options
    • A. 4494
    • B. 561.75
    • C. 2247
    • D. 280.875
    • E. None of these
    • Discuss
    • 5. The slant height of a right circular cone is 10 m and its height is 8 m. Find the area of its curved surface.

    • Options
    • A. 30Π m2
    • B. 40Π m2
    • C. 60Π m2
    • D. 80Π m2
    • Discuss
    • 6. If (64)2 - (36)2 = 20 x x, then x =?

    • Options
    • A. 70
    • B. 120
    • C. 180
    • D. 140
    • E. None of these
    • Discuss
    • 7. If n is a natural number, then (6n2 + 6n) is always divisible by:

    • Options
    • A. 6 only
    • B. 6 and 12 both
    • C. 12 only
    • D. by 18 only
    • Discuss
    • 8. Which of the following numbers will completely divide (4915 - 1)?

    • Options
    • A. 8
    • B. 14
    • C. 46
    • D. 50
    • Discuss
    • 9. The unit digit in the product (784 x 618 x 917 x 463) is:

    • Options
    • A. 2
    • B. 3
    • C. 4
    • D. 5
    • Discuss
    • 10. Which natural number is nearest to 9217, which is completely divisible by 88?

    • Options
    • A. 9152
    • B. 9240
    • C. 9064
    • D. 9184
    • E. None of these
    • Discuss


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