Let the edge of the large cube be a.
So, a3 = 216 ⟹ a = 6 cm.
∴ Required ratio = | ❨ | 6 x (32 + 42 + 52) | ❩ | = | 50 | = 25 : 18. |
6 x 62 | 36 |
Then, [(330 - 10) x (260 - 10) x (110 - x)] = 8000 x 1000
⟹ 320 x 250 x (110 - x) = 8000 x 1000
⟹ (110 - x) = | 8000 x 1000 | = 100 |
320 x 250 |
⟹ x = 10 cm = 1 dm.
⟹ h = | 180 | m = | 20 | m. |
27 | 3 |
∴ Volume = | ❨ | 15 x 12 x | 20 | ❩m3 | = 1200 m3. |
3 |
Radius = | 1 | mm | = | 1 | cm. | Then, |
2 | 20 |
⟹ | 22 | x | 1 | x | 1 | x h = 66. |
7 | 20 | 20 |
⟹ h = | ❨ | 66 x 20 x 20 x 7 | ❩ | = 8400 cm = 84 m. |
22 |
∴ Rise in water level = | ❨ | 200 | ❩m 0.25 m = 25 cm. |
40 x 20 |
So, l = √(7)2 + (14)2 = √245 = 7√5 cm.
∴ Total surface area | = Πrl + Πr2 | |||||||||
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= [154(√5 + 1)] cm2 | ||||||||||
= (154 x 3.236) cm2 | ||||||||||
= 498.35 cm2. |
Internal radius = 3 cm.
Volume of iron |
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= 462 cm3. |
∴ Weight of iron = (462 x 8) gm = 3696 gm = 3.696 kg.
So, Area = (1.5 x 10000) m2 = 15000 m2.
Depth = | 5 | m | = | 1 | m. |
100 | 20 |
∴ Volume = (Area x Depth) = | ❨ | 15000 x | 1 | ❩m3 | = 750 m3. |
20 |
b = (36 -16)m = 20 m,
h = 8 m.
∴ Volume of the box = (32 x 20 x 8) m3 = 5120 m3.
h = 8 m.
So, r = √l2 - h2 = √(10)2 - 82 = 6 m.
∴ Curved surface area = Πrl = (Π x 6 x 10) m2 = 60Π m2.
Given Exp. = 8988 x | 1 | x | 1 | = | 2247 | = 280.875 |
8 | 4 | 8 |
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