Radius = | 1 | mm | = | 1 | cm. | Then, |
2 | 20 |
⟹ | 22 | x | 1 | x | 1 | x h = 66. |
7 | 20 | 20 |
⟹ h = | ❨ | 66 x 20 x 20 x 7 | ❩ | = 8400 cm = 84 m. |
22 |
∴ Rise in water level = | ❨ | 200 | ❩m 0.25 m = 25 cm. |
40 x 20 |
So, l = √(7)2 + (14)2 = √245 = 7√5 cm.
∴ Total surface area | = Πrl + Πr2 | |||||||||
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= [154(√5 + 1)] cm2 | ||||||||||
= (154 x 3.236) cm2 | ||||||||||
= 498.35 cm2. |
Πr2h | = | 924 | ⟹ r = | ❨ | 924 | x 2 | ❩ | = 7 m. |
2Πrh | 264 | 264 |
And, 2Πrh = 264 ⟹ h = | ❨ | 264 x | 7 | x | 1 | x | 1 | ❩ | = 6m. |
22 | 2 | 7 |
∴ Required ratio = | 2r | = | 14 | = 7 : 3. |
h | 6 |
Clearly, we have r = 3 cm and h = 4 cm.
∴ Volume = | 1 | Πr2h = | ❨ | 1 | x Π x 32 x 4 | ❩cm3 | = 12Π cm3. |
3 | 3 |
Number of bricks = | Volume of the wall | = | ❨ | 800 x 600 x 22.5 | ❩ | = 6400. |
Volume of 1 brick | 25 x 11.25 x 6 |
⟹ h = | 180 | m = | 20 | m. |
27 | 3 |
∴ Volume = | ❨ | 15 x 12 x | 20 | ❩m3 | = 1200 m3. |
3 |
Then, [(330 - 10) x (260 - 10) x (110 - x)] = 8000 x 1000
⟹ 320 x 250 x (110 - x) = 8000 x 1000
⟹ (110 - x) = | 8000 x 1000 | = 100 |
320 x 250 |
⟹ x = 10 cm = 1 dm.
Let the edge of the large cube be a.
So, a3 = 216 ⟹ a = 6 cm.
∴ Required ratio = | ❨ | 6 x (32 + 42 + 52) | ❩ | = | 50 | = 25 : 18. |
6 x 62 | 36 |
Internal radius = 3 cm.
Volume of iron |
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= 462 cm3. |
∴ Weight of iron = (462 x 8) gm = 3696 gm = 3.696 kg.
So, Area = (1.5 x 10000) m2 = 15000 m2.
Depth = | 5 | m | = | 1 | m. |
100 | 20 |
∴ Volume = (Area x Depth) = | ❨ | 15000 x | 1 | ❩m3 | = 750 m3. |
20 |
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