Area of the wet surface | = [2(lb + bh + lh) - lb] |
= 2(bh + lh) + lb | |
= [2 (4 x 1.25 + 6 x 1.25) + 6 x 4] m2 | |
= 49 m2. |
Total increase in marks = | ❨ | x x | 1 | ❩ | = | x |
2 | 2 |
∴ | x | = (83 - 63) ⟹ | x | = 20 ⟹ x= 40. |
2 | 2 |
Sum of the present ages of wife and child = (20 x 2 + 5 x 2) years = 50 years.
∴ Husband's present age = (90 - 50) years = 40 years.
Weight of new person = (65 + 20) kg = 85 kg.
Required average |
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= 285 |
Required average |
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= 48.55 |
Volume of water displaced | = (3 x 2 x 0.01) m3 |
= 0.06 m3. |
∴ Mass of man | = Volume of water displaced x Density of water |
= (0.06 x 1000) kg | |
= 60 kg. |
Number of bricks = | Volume of the wall | = | ❨ | 800 x 600 x 22.5 | ❩ | = 6400. |
Volume of 1 brick | 25 x 11.25 x 6 |
Clearly, we have r = 3 cm and h = 4 cm.
∴ Volume = | 1 | Πr2h = | ❨ | 1 | x Π x 32 x 4 | ❩cm3 | = 12Π cm3. |
3 | 3 |
Πr2h | = | 924 | ⟹ r = | ❨ | 924 | x 2 | ❩ | = 7 m. |
2Πrh | 264 | 264 |
And, 2Πrh = 264 ⟹ h = | ❨ | 264 x | 7 | x | 1 | x | 1 | ❩ | = 6m. |
22 | 2 | 7 |
∴ Required ratio = | 2r | = | 14 | = 7 : 3. |
h | 6 |
So, l = √(7)2 + (14)2 = √245 = 7√5 cm.
∴ Total surface area | = Πrl + Πr2 | |||||||||
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= [154(√5 + 1)] cm2 | ||||||||||
= (154 x 3.236) cm2 | ||||||||||
= 498.35 cm2. |
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