Required average |
|
|||||
|
||||||
= 285 |
Required average |
|
|||||
|
||||||
|
||||||
= 48.55 |
Total quantity of petrol consumed in 3 years |
|
||||||||||||
|
|||||||||||||
|
Total amount spent = Rs. (3 x 4000) = Rs. 12000.
∴ Average cost = Rs. | ❨ | 12000 x 51 | ❩ | = Rs. | 6120 | = Rs. 7.98 |
76700 | 767 |
∴ Required sale = Rs. [ (6500 x 6) - 34009 ]
= Rs. (39000 - 34009)
= Rs. 4991.
Required run rate = | ❨ | 282 - (3.2 x 10) | ❩ | = | 250 | = 6.25 |
40 | 40 |
∴ Sum of 20 numbers (0 x 20) = 0.
It is quite possible that 19 of these numbers may be positive and if their sum is a then 20th number is (-a).
Weight of new person = (65 + 20) kg = 85 kg.
Sum of the present ages of wife and child = (20 x 2 + 5 x 2) years = 50 years.
∴ Husband's present age = (90 - 50) years = 40 years.
Total increase in marks = | ❨ | x x | 1 | ❩ | = | x |
2 | 2 |
∴ | x | = (83 - 63) ⟹ | x | = 20 ⟹ x= 40. |
2 | 2 |
Area of the wet surface | = [2(lb + bh + lh) - lb] |
= 2(bh + lh) + lb | |
= [2 (4 x 1.25 + 6 x 1.25) + 6 x 4] m2 | |
= 49 m2. |
Volume of water displaced | = (3 x 2 x 0.01) m3 |
= 0.06 m3. |
∴ Mass of man | = Volume of water displaced x Density of water |
= (0.06 x 1000) kg | |
= 60 kg. |
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.