Required average |
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= 48.55 |
Total quantity of petrol consumed in 3 years |
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Total amount spent = Rs. (3 x 4000) = Rs. 12000.
∴ Average cost = Rs. | ❨ | 12000 x 51 | ❩ | = Rs. | 6120 | = Rs. 7.98 |
76700 | 767 |
∴ Required sale = Rs. [ (6500 x 6) - 34009 ]
= Rs. (39000 - 34009)
= Rs. 4991.
Required run rate = | ❨ | 282 - (3.2 x 10) | ❩ | = | 250 | = 6.25 |
40 | 40 |
∴ Sum of 20 numbers (0 x 20) = 0.
It is quite possible that 19 of these numbers may be positive and if their sum is a then 20th number is (-a).
P + Q = (5050 x 2) = 10100 .... (i)
Q + R = (6250 x 2) = 12500 .... (ii)
P + R = (5200 x 2) = 10400 .... (iii)
Adding (i), (ii) and (iii), we get: 2(P + Q + R) = 33000 or P + Q + R = 16500 .... (iv)
Subtracting (ii) from (iv), we get P = 4000.
∴ P's monthly income = Rs. 4000.
Required average |
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= 285 |
Weight of new person = (65 + 20) kg = 85 kg.
Sum of the present ages of wife and child = (20 x 2 + 5 x 2) years = 50 years.
∴ Husband's present age = (90 - 50) years = 40 years.
Total increase in marks = | ❨ | x x | 1 | ❩ | = | x |
2 | 2 |
∴ | x | = (83 - 63) ⟹ | x | = 20 ⟹ x= 40. |
2 | 2 |
Area of the wet surface | = [2(lb + bh + lh) - lb] |
= 2(bh + lh) + lb | |
= [2 (4 x 1.25 + 6 x 1.25) + 6 x 4] m2 | |
= 49 m2. |
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