∴ Sum of 20 numbers (0 x 20) = 0.
It is quite possible that 19 of these numbers may be positive and if their sum is a then 20th number is (-a).
Given Expression = 3120 ÷ 26 + 13 x 30
= 120 + 13 x 30
= 120 + 390
= 510
According to the fundamental to the fundamental formula
Average(A)= Sum (S) / Number(N)
From the question 60 = S / 13
? S = 60 x 13 = 780
Sum of first seven result = 59 x 7 = 413
Sum of last seven result = 61 x 7 = 427
? 7th result = (Sum of first seven result) + (Sum of last seven results) - (Sum of all the results)
= (413 + 427 - 780 )
= (840 - 780)
= 60
NoteSum of first seven when added to the sum of last seven result, then repetition of 7th result takes place.
Original area = (22/7) x 9 x 9 cm2
New area = (22/7) x 7 x 7 cm2
? Decrease = 22/7 x [(9)2 -(7)2] cm2
=(22/7) x 16 x 2 cm2
Decrease percent = [(22/7 x 16 x 2) /( 7/22 x 9 x 9)] x 100 %
= 39.5 %
27 x 1.2 x 5.5262 x 0.6
= 27 x [(12 - 1) / 9] x [(55262 - 5526)/9000] x (6/9)
= (27 x 11)/9 x (49736/9000) x (6/9)
= 1094192 / 9000
= 121.576888...
= 121.5768
Let the two numbers be P and Q.
According to given question,
Sum of two numbers = 24
? P + Q = 24 ...................... (1)
Product of two numbers = 143
and, PQ = 143 .......................... (2)
As we know the formula,
? P 2 + Q2 = (P + Q)2 ? 2PQ
Put the value from the equation (1) and (2), We will get
? P 2 + Q2 = (24)2 ? 2 × 143
? P 2 + Q2 = 576 ? 286 = 290
? Probability that no man out of n men aged x years will die in a year = (1 - p)n
? Probability that out of n men at least one will die in a year = 1 - (1 - p)n .
When at least one, man dies, any one out of the n men may be the first to die
Given Exp.
= log (57 x 100 / 100) + 3log(0.57) + 1/2log(0.57)
= log (0.57) + log 102 + 3log(0.57) +1/2log (0.57)
= (1 + 3 + 1/2) log(0.57) + 2 [? log102 = 2]
= (4.5 x 1.756) + 2 = 4.5 x (-1 + 0.756) + 2
= 3.402 - 4.5 + 2
= 0.902
(?)2 = ?132 + 28 / 4 - (3)3 + 107
= ?169 + 7 - 27 + 107
= ?256
= ?16
= 4
Let A takes x and B takes 3N days to finish the job.
According to the question,
3N - N = 30
? N = 30/2 = 15 days
? B's time to complete the work = 3N
= 3 x 15 = 45 days
? (A + B)'s 1 day's work
= (1/15) + (1/45) = (3 + 1)/45 = 4/45
? (A + B) will finish the work in 4/45 days
? Required time = 4/45 = 111/4
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