Odd days in 1600 years = 0
Odd days in 400 years = 0
9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 odd days ≡ 4 odd days.
Jan. Feb. March April May June July Aug. (31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days
∴ 227 days = (32 weeks + 3 days) ≡ 3 odd days.
Total number of odd days = (0 + 0 + 4 + 3) = 7 ≡ 0 odd days.
Given day is Sunday.
Increase% = | ❨ | 87500 | x 100 | ❩% = 50%. |
175000 |
∴ Required average = | ❨ | 50 | ❩% = 5%. |
10 |
∴ Required percentage = | ❨ | 11628 | x 100 | ❩% = 57%. |
20400 |
x% of y = | ❨ | x | x y | ❩ | = | ❨ | y | x x | ❩ | = y% of x |
100 | 100 |
∴ A = B.
Number of students above 8 years of age = (100 - 20)% of x = 80% of x.
∴ 80% of x = 48 + | 2 | of 48 |
3 |
⟹ | 80 | x = 80 |
100 |
⟹ x = 100.
Then, (100 - 40)% of x = 420.
⟹ | 60 | x x = 420 |
100 |
⟹ x = | ❨ | 420 x 100 | ❩ = 700. |
60 |
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) ≡ 6 odd days
Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days
∴ 148 days = (21 weeks + 1 day) ≡ 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 ≡ 0 odd day.
Given day is Sunday.
So, after 63 days, it will be Monday.
∴ After 61 days, it will be Saturday.
Year : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017 Odd day : 1 2 1 1 1 2 1 1 1 2 1
Sum = 14 odd days ≡ 0 odd days.
∴ Calendar for the year 2018 will be the same as for the year 2007.
∴ Last day of 1st century is Friday.
200 years contain (5 x 2) ≡ 3 odd days.
∴ Last day of 2nd century is Wednesday.
300 years contain (5 x 3) = 15 ≡ 1 odd day.
∴ Last day of 3rd century is Monday.
400 years contain 0 odd day.
∴ Last day of 4th century is Sunday.
This cycle is repeated.
∴ Last day of a century cannot be Tuesday or Thursday or Saturday.
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.