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  • Question
  • Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?


  • Options
  • A. Rs. 6400
  • B. Rs. 6500
  • C. Rs. 7200
  • D. Rs. 7500
  • E. None of these

  • Correct Answer
  • Rs. 6400 

    Explanation
    Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x ).
    Then, x x 14 x 2 + (13900 - x) x 11 x 2 = 3508
    100 100

    ⟹ 28x - 22x = 350800 - (13900 x 22)

    ⟹ 6x = 45000

    x = 7500.

    So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.


  • More questions

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      The median for the data 2, 4, 6, 8, 10, 12, 14 is

    • Options
    • A. 6
    • B. 8
    • C. 9.5
    • D. 10
    • Discuss
    • 2. 
      The value of 47 / 10000 is?

    • Options
    • A. .0047
    • B. .0470
    • C. .00047
    • D. .000047
    • Discuss
    • 3. If 4x = 18y, then the value of ( x/y - 1) is

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    • A. 1 3
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    • 4. 
      If the price of 23 toys is Rs. 276, then what will the price (Rs.) of 12 toys?

    • Options
    • A. 144
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    • C. 159
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    • 5. 
      .02 =(......?.....)%

    • Options
    • A. 20
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    • 6. 
      If 36 men can do a piece of work in 25 hours, in how many hours will 15 men do it?

    • Options
    • A. 45
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    • 7. 
      2?63 / 11 =233

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    • 8. 
      When 121012 is divided by 12, the remainder is

    • Options
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    • 9. 
      Aarti can do a piece of work in 6 days. In how many days will she complete three time of work of same type?

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    • 10. 
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    • Options
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