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- Question
A train speeds past a pole in 15 seconds and a platform 100 m long in 25 seconds. Its length is:
Options- A. 50 m
- B. 150 m
- C. 200 m
- D. Data inadequate
- Correct Answer
- 150 m
Explanation
Let the length of the train be x metres and its speed by y m/sec.Then, x = 15 ⟹ y = x . y 15 ∴ x + 100 = x 25 15 ⟹ 15(x + 100) = 25x
⟹ 15x + 1500 = 25x
⟹ 1500 = 10x
⟹ x = 150 m.
- 1. Six bell commence tolling together and toll at intervals of 5, 10, 15, 20, and 30 s, respectively. In 60 min, how many times do they toll together?
Options- A. 20
- B. 15
- C. 13
- D. 11 Discuss
- 2. In the given figure, ?B = ?C = 55° and ?D = 25°. Then:
Options- A. BC < CA < CD
- B. BC > CA > CD
- C. BC < CA, CA > CD
- D. BC > CA, CA < CD Discuss
- 3. In the given figure, AB || CD and AC || BD. If ?EAC = 40°, ?FDG = 55°, ?HAB = x; then the value of x is:
Options- A. 95°
- B. 70°
- C. 35°
- D. 85° Discuss
- 4. The complement of an angle exceeds the angle by 60°. Then the angle is equal to:
Options- A. 25°
- B. 30°
- C. 15°
- D. 35° Discuss
- 5. Find the measure of an angle, if six times its complement is 12° less than twice its supplement :
Options- A. 48°
- B. 96°
- C. 24°
- D. 58° Discuss
- 6. In the adjoining figure, AB || CD, t is the traversal, EG and FG are the bisectors of ?BEE and ?DFE respectively, then ?EGF is equal to :
Options- A. 90°
- B. 75°
- C. 80°
- D. 110° Discuss
- 7. The complement of 30°20? is:
Options- A. 69°40?
- B. 59°40?
- C. 35°80?
- D. 159°40? Discuss
- 8. In the given, AB || CD. Then X is equal to:
Options- A. 93°
- B. 103°
- C. 83°
- D. 97° Discuss
- 9. In what ratio must a grocer mix sugar at 72 paise per kg with sugar at 48 paise per kg. So that by selling the mixture at
63 paise per kg he may gain 1 of his out-lay? 6
Options- A. 1 : 3
- B. 3 : 1
- C. 2 : 3
- D. 3 : 2 Discuss
- 10. A Principal amounts to ? 944 in 3 yr and to ? 1040 in 5 yr, each sum being invested at the same simple interest. The principal was
Options- A. ? 800
- B. ? 991
- C. ? 750
- D. ? 900 Discuss
More questions
Correct Answer: 13
Explanation:
LCM of 5, 10, 15, 20, 25 and 30 is 300. So, the bell will toll together after every 300s (5min).
So, the number of times they toll together = 60/5 + 1=13
Correct Answer: BC > CA, CA < CD
Explanation:
According to question,
?B = ?C = 55° , ?D = 25°
We can say ,
AB = AC ( ? ?B = ?C = 55° )
In Triangle ABC,
?A + ?B + ?C = 180°
? ?A + 55° + 55° = 180°
? ?A + 110° = 180°
? ?A = 180° - 110°
? ?A = 70° ..........................(1)
As per given figure,
?ACD + ?ACB = 180° ( ?ACB = ?C = 55°)
? ?ACD + 55° = 180°
? ?ACD = 180° - 55°
? ?ACD = 125° ....................... (2)
Now in Triangle ACD,
?CAD + ?ACD + ?CDA = 180°
? ?CAD + 125° + 25° = 180°
? ?CAD + 150° = 180°
? ?CAD = 30° ...........................(3)
( In a ?, greater angle has longer side opposite to it )
From the equation (1) , (2) and (3);
?B < ?A and ?CAD > ?D ;
? BC > CA and CA < CD
Correct Answer: 85°
Explanation:
?DCK = ?FDG = 55° (corr. ?s)
? ?ACE = ?DCK = 55° (vert. opp. ?s)
So, ?AEC = 180° ? (40° + 55°) = 85°
? ?HAB = ?AEC = 85° (corr. ?s)
Hence, x = 85°.
Correct Answer: 15°
Explanation:
Let, the angle be A
? Its complement angle = 90° ? A
According to the question
(90 ? A) = A + 60°
? 90 - 60 = A + A
? 2A = 30°
? A = 15°
Correct Answer: 48°
Explanation:
Let, the measure of the required angled be A°.
Then, measure of its complement = ( 90 ? A )° measure of its supplement = (180 ? A)°
According to question,
6(90° ? A) = 2(180° ? A) ?12°
? 540° ? 6A = 360° ? 2A ? 12°
? 4A = 192°
? A = 48°.
Correct Answer: 90°
Explanation:
Correct Answer: 59°40?
Explanation:
complement of 30°20? = 90° ? ( 30°20? ) = 90° ? ( 30° + 20? )
= (89° ? 30°) + (1° ? 20?)
= 59° + 60? ? 20? [ ? 1° = 60°?]
= 59° + 40? = 59°40?.
Correct Answer: 97°
Explanation:
Through O, draw a line l parallel to both AB and CD. Then
?1 = 45° (alt. ?S)
and ?2 = 30° (alt. ?S)
? ?BOC = ?1 + ?2 = 45° + 30° = 75°
So, X = 360° ? ?BOC = 360° ? 75° = 285°
Hence X = 285°.
Correct Answer: 1 : 3
Explanation:
Correct Answer: ? 800
Explanation:
By formula, P = (A2T1 - A1T2) / (T1 - T2)
Here, A1 = ? 944, T1 = 3
A2 = ? 1040, T2 = 5
? P = [(1040 x 3) - (944 x 5)] / (3 - 5)
= (3120 - 4720) / (-2)
= (-1600) / (-2)
= ? 800
? Principal = ? 800
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