Manideep purchases 30kg of barley at the rate of 11.50/kg and 20kg at the rate of 14.25/kg. He mixed the two and sold the mixture in the shop. At what price per kg should he sell the mixture to make 30% profit to him?

Correct Answer: 25%

Explanation:

He has gain = 15 - 12 = 3,
Gain% = (3/12) x 100 = (100/4) = 25.
He has 25% gain.

Correct Answer: 60

Explanation:

Let M litres milk be added

=> 60 + M 40 = 3 1

=> 60 + M = 120

=> M = 60 lit.

Correct Answer: 105/103

Explanation:

As given equal amounts of alloys are melted, let it be 1 kg.

Required ratio of gold and silver =  5 13 + 5 8 8 13 + 3 8 = 105 103 .

 

Hence, ratio of gold and silver in the resulting alloy = 105/103.

Correct Answer: 60 lit

Explanation:

Correct Answer: 87.48 lit

Explanation:

For these type of problems,

Quantity of Diesel remained =  q 1 - p q n   

 

Here p = 12 , q = 120 

 

=>  120 1 - 12 120 3 = 120 x 0.9 x 0.9 x 0.9 = 87.48 lit.

Correct Answer: Rs. 25.69

Explanation:

Rate of rice of quantity 280 kg = Rs. 15.60/kg

Rate of rice of quantity 120 kg = Rs. 14.40/kg

He want to earn a profit of Rs. 10.45/kg

Rate of Mix to sell to get profit of 10.45 =  

 

$$\begin{gathered} 280 x 15 . 60 + 120 x 14 . 40 280 + 120 + 10 . 45 \\ 4368 + 1728 400 + 10 . 45 \\ = > 15 . 24 + 10 . 45 \\ = 25 . 69 \end{gathered}$$

Correct Answer: 3 : 2

Explanation:

% of milk in first bottle = 64%

% of milk in second bottle = 100 - 26 = 74%

Now, ATQ

 

64%            74%
         

         68%

 

6                    4

 

Hence, by using allegation method,

 

Required ratio = 3 : 2

Correct Answer: 2:1

Correct Answer: 320 ml

Explanation:

Here total parts of milk and water in the solution is 6+2 = 8 parts.

1part = 640/8 = 80

 

old mixture contains 6parts of milk and 2 parts of water(6:2).

 

To get new mixture containing half milk and half water, add 4parts of water to the old mixture then 6:(2+4) to make the ratio same.

i.e, 4 x 80 = 320 ml.

Correct Answer: 5

Explanation:

Let x litre pepsi is required.

 

 

(10-9)=1           :                3=(9-6)

 

Therefore  in 1:3 one part = 5 

 

=>  x= 5 litres