The amount of water (in ml) that should be added to reduce 9 ml lotion, containing 50% alcohol, to a lotion containing 30% alcohol is?

Correct Answer: 1:1

Explanation:

Quantity of alohol in the mixture = 40 x 5/8 = 25 lit

Quantity of water = 40 - 25 = 15 lit

According to question,

Required ratio =  20 - 40 x 20 100 x 5 8 15 - 40 x 20 100 x 3 8 + 40 x 20 100 = 20 15 - 3 + 8 = 1 : 1

Correct Answer: 160

Explanation:

Applying Allegation Method to first calculate the ratio in which they have to be mixed: = 8 : 12 = 2 : 3
Thus, the two varieties of oil should be mixed in the ratio 2 : 3. So, if 240 liters of the second variety are taken, then 160 liters of the first variety should be taken

Correct Answer: 76.92%

Explanation:

Let the milk he bought is 1000 ml

Let C.P of 1000 ml is Rs. 100

Here let he is mixing K ml of water

He is getting 30% profit

=> Now, the selling price is also Rs. 100 for 1000 ml

=> 100 : K%

= 100 : 30

10 : 3 is ratio of milk to water

=> Percentage of milk = 10 x 100/13 = 1000/13 = 76.92%

Correct Answer: 29.63 litres

Explanation:

Given that container has 50 litres of milk.

 After replacing 8 litres of milk with water for three times, milk contained in the container is:

  ? 50 1 - 8 50 3

? 50 × 42 50 × 42 50 × 42 50  = 29.63 litres.

Correct Answer: 49 : 221

Explanation:

Copper in 4 kg = 4/5 kg          and      Zinc in 4 kg = 4 x (4/5) kg

 

Copper in 5 kg = 5/6 kg          and      Zinc in 5 kg = 5 x (5/6) kg

 

Therefore, Copper in mixture =  4 5 + 5 6 = 49 30 kg

 

and  Zinc in the mixture = 16 5 + 25 6 = 221 30kg

 

Therefore the required ratio = 49 : 221

Correct Answer: 2 lit

Explanation:

Quantity of fruit juice in the mixture = 70 - [70 x (10/100) ]= 63 litres.

 

After adding water, juice would form 87.5% of the mixture.

 

Hence, if quantity of mixture after adding x liters of water, [(87.5) /100 ]*x = 63 => x = 72 

 

Hence 72 - 70 = 2 litres of water must be added.

Correct Answer: 7:3

Explanation:

Ratio of Milk and water in a vessel A is 4 : 1

 

Ratio of Milk and water in a vessel B is 3 : 2

 

Ratio of only milk in vessel A = 4 : 5

 

Ratio of only milk in vessel B = 3 : 5

 

Let 'x' be the quantity of milk in vessel C

 

Now as equal quantities are taken out from both vessels A & B

 

=> 4/5     :     3/5
               x 
  3/5-x          x - 4/5

 

=> 3 5 - x x - 4 5 = 1 1 (equal quantities)

 

=> x = 7/10

 

Therefore, quantity of milk in vessel C  = 7

 

=> Water quantity = 10 - 7 = 3

 

Hence the ratio of milk & water in vessel 3 is 7 : 3 

Correct Answer: 3:2

Explanation:

Concentration of glucose are in the ratio = 1 2 : 3 5 : 4 5

Quantity of glucose taken from A = 1 liter out of 2

Quantity of glucose taken from B = 3/5 x 3 = 1.5 lit

Quantity of glucose taken from C = 0.8 lit

So, total quantity of glucose taken from A,B and C = 3.6 lit

So, quantity of alcohol = (2 + 3 + 1) - 3.6 = 2.4 lit

Ratio of glucose to alcohol = 3.6/2.4 = 3:2

Correct Answer: 27 %

Explanation:

Let the percentage of benzene = X
(30 - X)/(X- 25) = 6/4 = 3/2
=> 5X = 135  
X = 27

So, required percentage of benzene = 27 %

Correct Answer: 193 : 122

Explanation:

Given the three mixtures ratio as (1:2),(2:3),(3:4)

(1+2),(2+3),(3+4)

Total content = 3,5,7

 

Given equal quantities of the three mixtures are mixed, then LCM of 3, 5, 7 = 105

105/3 = 35 , 105/5 = 21 , 105/7 = 15

 

Now, the individual equal quantity ratios are (35x1, 35x2), (21x2, 21x3), (15x3, 15x4)

 i.e (35,70), (42,63), (45,60)

 

So overall mixture ratio of milk and water is

35+42+45 : 70+63+60

122:193

 

But in the question asked the ratio of water to milk = 193 : 122