A tin a mixture of two liquids A and B in the proportion 4 : 1. If 45 litres of

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A tin a mixture of two liquids A and B in the proportion 4 : 1. If 45 litres of the mixture is replaced by 45 litres of liquid B, then the ratio of the two liquids becomes 2 : 5. How much of the liquid B was there in the tin? What quantity does the tin hold?
Options
A. 58 l
B. 65 l
C. 50 l
D. 62 l

Correct Answer

50 l

Explanation

Let the tin contain 5x litres of liquids

$\frac{(5 x - 45) x \frac{4}{5}}{(5 x - 45) x \frac{1}{5} + 45} = \frac{2}{5}$

=> 5(4x - 36) = 2(x + 36)

=> 20x - 180 = 2x + 72

=> x = 14 litres

Hence, the initial quantity of mixture = 70l

Quantity of liquid B

= $(70 - 45) x \frac{1}{5} + 45$

= 50 litres.

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Comments

∴ T.D. on Rs. 260 = Rs.	❨	10	x 260	❩	= Rs. 10.40
		250

S.I. on Rs. 540 = Rs.	❨	90	x 540	❩	= Rs. 108.
		450

Saving % =	❨	0.59x	x 100	❩%	= 30% (approx.)
		2x

A : B = 2 : 3 and B : C = 5 : 8 =	❨	5 x	3	❩	:	❨	8 x	3	❩	= 3 :	24
			5					5			5

⟹ B =	❨	98 x	15	❩	= 30.
			49

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A tin a mixture of two liquids A and B in the proportion 4 : 1. If 45 litres of the mixture is replaced by 45 litres of liquid B, then the ratio of the two liquids becomes 2 : 5. How much of the liquid B was there in the tin? What quantity does the tin hold?

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Discussion

A tin a mixture of two liquids A and B in the proportion 4 : 1. If 45 litres of the mixture is replaced by 45 litres of liquid B, then the ratio of the two liquids becomes 2 : 5. How much of the liquid B was there in the tin? What quantity does the tin hold?

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