Profit (%) = 9.09 % = 1/11
Since the ratio of water and milk is 1 : 11,
Therefore the ratio of water is to mixture = 1:12
Thus the quantity of water in mixture of 1 liter = 1000 x (1/12) = 83.33 ml
pool : kerosene
3 : 2(initially)
2 : 3(after replacement)
(for petrol)
=> K = 30
Therefore the total quantity of the mixture in the container is 30 liters.
Wine Water
8L 32L
1 : 4
20 % 80% (original ratio)
30 % 70% (required ratio)
In ths case, the percentage of water being reduced when the mixture is being replaced with wine.
so the ratio of left quantity to the initial quantity is 7:8
Therefore ,
=> K = 5 Lit
Let the price of the mixed variety be Rs. x per kg. By the rule of alligation, we have :
Cost of 1 kg of type 1 rice Cost of 1 kg of type 2 rice
(20-x)/(x-15) = 2/3
60 - 3x = 2x - 30
x = 18.
By the rule of alligation:
C.P. of 1 kg sugar of 1st kind C.P. of 1 kg sugar of 2nd kind
Therefore, Ratio of quantities of 1st and 2nd kind = 14 : 6 = 7 : 3.
Let x kg of sugar of 1st kind be mixed with 27 kg of 2nd kind.
Then, 7 : 3 = x : 27 or x = (7 x 27 / 3) = 63 kg.
Number of liters of water in 125 liters of the mixture = 20% of 150 = 1/5 of 150 = 30 liters
Let us Assume that another 'P' liters of water are added to the mixture to make water 25% of the new mixture. So, the total amount of water becomes (30 + P) and the total volume of the mixture becomes (150 + P)
Thus, (30 + P) = 25% of (150 + P)
Solving, we get P = 10 liters
Total no.of boys : no. of girls = 13:27
27 : 13
By the rule of alligation:
Cost of 1 kg rice of 1st kind Cost of 1 kg rice of 2nd kind
Required ratio = 60 : 90 = 2 : 3
2 : 3 4 : 5 5 : 7
= 72/180
= 80/180
= 75/180
=> 5 : 3
Therefore, the ratio is 5: 3
Total quantity of mixture = 75 litre
Milk : Water = 4 : 1
3 : 1
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.