Number of students behind Manoj in rank = (31 - 7) = 24.
So, Manoj is 25th from the bottom.
Number of students behind Satya in rank = (31 - 11) = 20.
So, Satya is 21st from the bottom.
If the year is not a leap year, then last day is same as first day
The 2nd, 4th, 7th digits are 3, 1, 6 respectively.
The perfect square of a two-digit odd number, formed using these digits, is 361
and 361 = 19^2
Given Number : 2 5 6 7 3 9 4 8
Ascending order : 2 3 4 5 6 7 8 9
Specified letters are 6 and 4 respectively.
Hence, required sum = (4 + 6 = 10)
Number of days = (6 + 29 + 31 + 30 + 15) = 111
2008 is a leap year, number of days in february = 29
If day before yesterday was Thursday, then today is saturday.
Tomorrow will be sunday
Total days from 25th June to 15th August = 5 + 31 + 15 = 51 days
51/7 = 7 weeks and 2 days
August 15 = Wednesday + 2 = Friday
The given numbers are :
382 473 568 728 847 629
When changes are made as given in the question, numbers become as follows :
238 347 856 872 784 962
Again now, find out the difference between the numbers given in options as given below:
(1) 473 - 382 => 347 - 238 = 109
(2) 629 - 728 => 962 - 872 = 90
(3) 629 - 847 => 962 - 784 = 178
(4) 728 - 847 => 872 - 784 = 88
W = 10th from the left
R = 4th from the right = (30 - 4 + 1= ) 27th from left
No of boys between R and W = (27 - 10) - 1 = 16
Here the given numbers are
567 284 696 865 738
When 1 is added to the last digit of each of the above numbers, it becomes as follows :
568 285 697 866 739
After reversing the order of digits , we get
865 582 796 668 937
Now , when the numbers are arranged in ascending order their order becomes as follows:
582 668 796 865 937
Hence , the fourth number is 865 (a number formed by 567). Therefore option(1) is correct answer.
Initialy from left 7th = kumar
from right 9th = pawan
Interchange kumar = 11th from left, from right kumar = 9th;
11+8 = 19;
8 is 1,2,3,4,5,6,7(pawan),8,9,10,11(kumar),12,13,14,15,16,17,18,19;
simply count the 9th place from right we will get total as 19.
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