If the year is not a leap year, then last day is same as first day
The 2nd, 4th, 7th digits are 3, 1, 6 respectively.
The perfect square of a two-digit odd number, formed using these digits, is 361
and 361 = 19^2
Given Number : 2 5 6 7 3 9 4 8
Ascending order : 2 3 4 5 6 7 8 9
Specified letters are 6 and 4 respectively.
Hence, required sum = (4 + 6 = 10)
Number of days = (6 + 29 + 31 + 30 + 15) = 111
2008 is a leap year, number of days in february = 29
If day before yesterday was Thursday, then today is saturday.
Tomorrow will be sunday
Dates on which Tuesday fall are 3,10,17, and 24
Hence, the 27th day of the month will be (Tuesday + 3 days=)Friday
Required day of the month = Friday - 4 = Monday
Number of students behind Manoj in rank = (31 - 7) = 24.
So, Manoj is 25th from the bottom.
Number of students behind Satya in rank = (31 - 11) = 20.
So, Satya is 21st from the bottom.
Total days from 25th June to 15th August = 5 + 31 + 15 = 51 days
51/7 = 7 weeks and 2 days
August 15 = Wednesday + 2 = Friday
The given numbers are :
382 473 568 728 847 629
When changes are made as given in the question, numbers become as follows :
238 347 856 872 784 962
Again now, find out the difference between the numbers given in options as given below:
(1) 473 - 382 => 347 - 238 = 109
(2) 629 - 728 => 962 - 872 = 90
(3) 629 - 847 => 962 - 784 = 178
(4) 728 - 847 => 872 - 784 = 88
W = 10th from the left
R = 4th from the right = (30 - 4 + 1= ) 27th from left
No of boys between R and W = (27 - 10) - 1 = 16
Here the given numbers are
567 284 696 865 738
When 1 is added to the last digit of each of the above numbers, it becomes as follows :
568 285 697 866 739
After reversing the order of digits , we get
865 582 796 668 937
Now , when the numbers are arranged in ascending order their order becomes as follows:
582 668 796 865 937
Hence , the fourth number is 865 (a number formed by 567). Therefore option(1) is correct answer.
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