Number of days = (6 + 29 + 31 + 30 + 15) = 111
2008 is a leap year, number of days in february = 29
If day before yesterday was Thursday, then today is saturday.
Tomorrow will be sunday
Dates on which Tuesday fall are 3,10,17, and 24
Hence, the 27th day of the month will be (Tuesday + 3 days=)Friday
Required day of the month = Friday - 4 = Monday
The new number formed is 4 3 0 1 8 2 7 9 6 5
The seventh digit from the left is 7, the 3rd digit from the left of 7 is 1
We have to find out even number - even number - odd number sequence.
8 5 8 6 7 6 8 9 3 2 7 5 3 4 2 2 3 5 5 2 2 8 1 1 9 3 1 7 5 1
There are four such such even numbers: 6,8,2 and 8.
Given Number : 2 5 6 7 3 9 4 8
Ascending order : 2 3 4 5 6 7 8 9
Specified letters are 6 and 4 respectively.
Hence, required sum = (4 + 6 = 10)
The 2nd, 4th, 7th digits are 3, 1, 6 respectively.
The perfect square of a two-digit odd number, formed using these digits, is 361
and 361 = 19^2
If the year is not a leap year, then last day is same as first day
Number of students behind Manoj in rank = (31 - 7) = 24.
So, Manoj is 25th from the bottom.
Number of students behind Satya in rank = (31 - 11) = 20.
So, Satya is 21st from the bottom.
Total days from 25th June to 15th August = 5 + 31 + 15 = 51 days
51/7 = 7 weeks and 2 days
August 15 = Wednesday + 2 = Friday
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