We have to find out even number - even number - odd number sequence.
8 5 8 6 7 6 8 9 3 2 7 5 3 4 2 2 3 5 5 2 2 8 1 1 9 3 1 7 5 1
There are four such such even numbers: 6,8,2 and 8.
M is 8th from the top.
H is (50 - 20 + 1 =) 31 st from the top.
Number of students between M and H = (31 - 8- 1=)22
Only one such symbol is there in the given arrangement.
It is 4@5.
There are 10 digits. Now, third digit from the right means (10-3+1 = ) 8th digit from the left. But, from the question , third and eighth digits are interchanged. Hence, the required digit is the third digit of the given number, ie 0.
The possibe two-digit numbers are: 88, 85, 82, 81, 87, 86, 58, 28, 18, 78, 68
These are 11 in number
The new number formed is 4 3 0 1 8 2 7 9 6 5
The seventh digit from the left is 7, the 3rd digit from the left of 7 is 1
Dates on which Tuesday fall are 3,10,17, and 24
Hence, the 27th day of the month will be (Tuesday + 3 days=)Friday
Required day of the month = Friday - 4 = Monday
If day before yesterday was Thursday, then today is saturday.
Tomorrow will be sunday
Number of days = (6 + 29 + 31 + 30 + 15) = 111
2008 is a leap year, number of days in february = 29
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