30th january, 2003 was thursday.
So, 6th, 13th, 20th, 27th february were all thursdays.
thus 2nd march, 2003 was 3 days after thursday, i.e. , sunday
Given Number : 7346285
Ascending Number : 2345678
Answer is Two. Those digits are 3,4
Three persons A, B, C can be arranged in a queue in six different ways, ie ABC, CBA, BAC, CAB, BCA, ACB. But since there are only 3 persons ahead of C, so C should be in front of the queue. Thus, there are only two possible arrangements, ie CBA and CAB.
We may consider the two cases as under:
Case I:
Clearly, number of persons in the queue = (3+1+8+1+5+1+21=) 40
Case II:
Number of persons between A and C
= (8 - 6) = 2
Clearly number of persons in the queue = (3+1+2+1+21) = 28
Now, 28 < 40. So, 28 is the minimum number of persons in the queue.
Number of boys in the class = (18 + 1 +18) = 37
Number of students in class = (8 + 1 + 37) = 46
Number students behind the nitin in rank = (49 - 18) = 31
Nitin is 32nd from the last
No. of boys up to the 34th rank = 34-18 = 16
Total no of boys = 180x1/2+1 = 60
number of boys after the rank of Rupesh = 60 - 16 = 44
Number of persons between Amrita and Mukul = 50 - (10 + 25) = 15. Since Mamta lies in middle of these 15 persons, so Mamta`s position is 8th from Amrita i.e. 18th from the front.
Number of boys in the row = (6 + 10 + 8) = 24
The 4th day is tuesday, then 11, 18, 25th also tuesdays
Then 3 days after 24th is 27th, which is thursday
Total number of students in the class = 28 + 6 i.e, from top(7-1)
28 + 6 = 34
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