Given Number : 7346285
Ascending Number : 2345678
Answer is Two. Those digits are 3,4
Three persons A, B, C can be arranged in a queue in six different ways, ie ABC, CBA, BAC, CAB, BCA, ACB. But since there are only 3 persons ahead of C, so C should be in front of the queue. Thus, there are only two possible arrangements, ie CBA and CAB.
We may consider the two cases as under:
Case I:
Clearly, number of persons in the queue = (3+1+8+1+5+1+21=) 40
Case II:
Number of persons between A and C
= (8 - 6) = 2
Clearly number of persons in the queue = (3+1+2+1+21) = 28
Now, 28 < 40. So, 28 is the minimum number of persons in the queue.
Number of boys in the class = (18 + 1 +18) = 37
Number of students in class = (8 + 1 + 37) = 46
Number students behind the nitin in rank = (49 - 18) = 31
Nitin is 32nd from the last
Clearly, A?s new position is 15th from the left. But this is the same as B?s earlier position which is 9th from the right.
30th january, 2003 was thursday.
So, 6th, 13th, 20th, 27th february were all thursdays.
thus 2nd march, 2003 was 3 days after thursday, i.e. , sunday
No. of boys up to the 34th rank = 34-18 = 16
Total no of boys = 180x1/2+1 = 60
number of boys after the rank of Rupesh = 60 - 16 = 44
Number of persons between Amrita and Mukul = 50 - (10 + 25) = 15. Since Mamta lies in middle of these 15 persons, so Mamta`s position is 8th from Amrita i.e. 18th from the front.
Number of boys in the row = (6 + 10 + 8) = 24
The 4th day is tuesday, then 11, 18, 25th also tuesdays
Then 3 days after 24th is 27th, which is thursday
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