Similarly ,
The correct pattern is *1+1, *2+2, *3+3, *4+4, . . . . .
So,32 is wrong term and must be replaced by (10 * 3 + 3) = 33
Let first no. be "k" and multiple be "l"...start value of y with 3
then,
[(k x y) + {l x (l-1)}]
Thus, we get
15 x 3 + 3 x 2 = 51
51 x 4 + 4 x 3 = 216
216 x 5 + 5 x 4 = 1100
1100 x 6 + 6 x 5 = 6630
6630 x 7 + 7 x 6 = 46452
Therefore, the missing number is 6630.
The given series follows,
2
2 x 2 = 4
4 x 3 = 12
12 x 4 = 48
48 x 5 = 240.
one of the letter from beginning and one of the letter from the end of a term are removed, one by one, alternate steps
3
3 x 1.5 + 1.5 = 6
6 x 2.5 + 2.5 = 17.5
17.5 x 3.5 + 3.5 = 64.75
64.75 x 4.5 + 4.5 = 295.875
In the given series,
2nd term =
3rd term =
and so on...
Here 6th term =
Therefore, 22 is wrong.
In the given series,
2nd term = 1st term + = 4 +1 = 5
3rd term = 2nd term + =5+4= 9
4th term = 3rd term + =9+9=18
5th term = 4th term + = 18+16=34
Therefore, odd term is 32
The series rtus/rtus/rtus/rtus. Thus, the pattern 'rtus' is repeated.
It follows the rule that
1
2x2
3x3x3
4x4x4x4
5x5x5x5x5
So the missing number is 4x4x4x4 = 256.
Here the first letter of the group is moved with a gap of one letter, the second letter of the group is backwardness and the third letter of the group is forwardness proceeding like this we get the letter group "JGW"
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.