From both the given statements, we find that : Praveen's salary s 115% of (90% of Rs 2500) = Rs 2587.50
So, both I and II are required.
From I. we have A <B< D.
From II. we have C < B
Combining( I) and (II), we can conclude that D is the heaviest
So. both the statements are needed
Statement II reveals that Satish met his friend Kapil on the day prior to Friday i.e, Thursday.
Thus, only II is needed.
From II. we can conclude that 500 boxes were sold on Sunday
From I. we find that number of boxes sold on Monday 500 +10% of 500 = 550.
From III, we have : Rajan's basic salary = Rs 1550.
From I, we have : Vasu's basic salary = Rs (1550 + 100) = Rs 1650.
From II. we have : Rajan's other allowances = RS 2000
and Vasu's other allowances = Rs 2050.
Vasu's monthly salary is (1650 + 2050) = Rs 3700.
Thus, all the three statements are required.
From statement II, we conclude that Sonali left her home 45 minutes before 10.15 a.m. i.e, 9.30 a.m.
Thus, only Ills needed
II reveals that the previous bus had left al 7.45 p.m
As given in I, the next has would leave after 30 minutes i.e, at 8.15 p.m.
Clearly, even both the statements together do not reveal Manohar's birthday.
Clearly, we have the order : A. a E. From I, we have the order : D, A, B. E.
From II, we get the complete sequence as D, A, B. E, C.
Clearly. B is in the middle. So, both I and II are required.
From statement I. we can conclude that the Chairman visited Purchase department on Monday of the first week of September. So, I alone is sufficient, The time of visit of no department is mentioned in II. which is, therefore, insufficient
The area of the plot can be determined from both I and II as follows .
Let the breadth of the plot be x metres Then, length = (x + 4) metres
Thus, perimeter s 208 metres 2(x + 4 + x) = 208 ,
4x =200, x = 50.
So. length =54 metres. breadth = 50 metres.
Area of the plot = 2700 m^2.
Hence, both I and II are required
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