Clearly, both the statements together are not sufficient to answer the question.
From I and II we find that 200 pages before Sunday
the last 40 pages on Monday. This means that he read (300 - (200 + 40)) = 60 pages on Sunday.
To find the rank from other end, we need to know the total number of students in the class. So. I is sufficient. Also: from II, we can conclude that there are (10 + 38- 1 = 47) students in the class.
So. II alone is also sufficient.
From I, we have : M>V, V> S, V > N.
From II. we have : Mukul is the oldest.
From 111, we have : S > N Combining (I) and (III) we get : M> V, V >S>N or M > V> S > N.
Clearly, Nikunj is the youngest.
From 1, we find that
Total money with Naresh and Ajay = Rs {(28/1OO)x 75000} = 21000.
From II, we find that money with Ajay = Rs {(3/4) x 21000 } = 15750.
So, both I and II art required
From I and II. we conclude that Mathematics period began at 9.00 a.m., Biology period began at 8.00 a.m. and Physics period began at 11 a.m. So. the Chemistry period began at 10.00 a.m. From I and III, we conclude that Mathematics period ended and Chemistry period began at 10.00 a.m.
From statement II, we conclude that Sonali left her home 45 minutes before 10.15 a.m. i.e, 9.30 a.m.
Thus, only Ills needed
From III, we have : Rajan's basic salary = Rs 1550.
From I, we have : Vasu's basic salary = Rs (1550 + 100) = Rs 1650.
From II. we have : Rajan's other allowances = RS 2000
and Vasu's other allowances = Rs 2050.
Vasu's monthly salary is (1650 + 2050) = Rs 3700.
Thus, all the three statements are required.
From II. we can conclude that 500 boxes were sold on Sunday
From I. we find that number of boxes sold on Monday 500 +10% of 500 = 550.
Statement II reveals that Satish met his friend Kapil on the day prior to Friday i.e, Thursday.
Thus, only II is needed.
From I. we have A <B< D.
From II. we have C < B
Combining( I) and (II), we can conclude that D is the heaviest
So. both the statements are needed
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