From II, we conclude that B is the brother-in law of M. So, even from both the statements, we can't find out who is the father of M
Clearly, each of the given statements shows that B is sitting opposite to C or B is the partner of C.
According to Pradeep : 20,21 or 22...(1)
According to his brother : not 22....(2)
From (1)&(2), the birthday falls on February 20 or 21.
From statements I and II together, we can conclude only that either B is the sister or brother of A.
So, even from both the statements, the exact relation cannot be known.
Comparing the information in the question with statement 1. we find that '2' and '9' are the codes for 'tie' and 'dip'. So, '7' represents 'button'.
Thus, I alone iS sufficient.
Again, comparing the information in the question with II, WO find that the common code number '7' stands for the common word 'button'.
Thus, II alone also is sufficient.
From both the given statements, we find that the number of cards sold this year (2935 x 1.2) = 3522.
S0. both I and II together are required.
From II, we know that Copal's brother was born in 1982. From III, we find that Gopal's brother was 8 years younger to him i.e. Copal was born in 1974. From I, we find that Sanjay is 6 years older than Gopal Thus. Sanjay was born in 1968. So. all the three statements are required.
From I, we conclude that F is the son of B.
From II, we conclude that B's wife is D's mother.
This means that D and F are the sons of B and D is the brother of F.
So, both I and II are required.
From I and II. we conclude that Mathematics period began at 9.00 a.m., Biology period began at 8.00 a.m. and Physics period began at 11 a.m. So. the Chemistry period began at 10.00 a.m. From I and III, we conclude that Mathematics period ended and Chemistry period began at 10.00 a.m.
From 1, we find that
Total money with Naresh and Ajay = Rs {(28/1OO)x 75000} = 21000.
From II, we find that money with Ajay = Rs {(3/4) x 21000 } = 15750.
So, both I and II art required
From I, we have : M>V, V> S, V > N.
From II. we have : Mukul is the oldest.
From 111, we have : S > N Combining (I) and (III) we get : M> V, V >S>N or M > V> S > N.
Clearly, Nikunj is the youngest.
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