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- Question
If 'HARBOUR' is written as 'IBSCPVS' , how is 'HABITAT' written in that code?
Options- A. GZAHSZS
- B. IBCJUBU
- C. IBAHSZS
- D. IBCJBUU
- Correct Answer
- IBCJUBU
- 1. The solution of 3(2u + v) = 7 uv and 3(u + 3v) = 11 uv is _____
Options- A. u = 1, v = 0
- B. u = 1, v = 3/2
- C. u = 0, v = 3/4
- D. u = 0, v = 1 Discuss
- 2. What approximate value will come in place of question mark (?) in the following question ? (49.001)2 = ?
Options- A. 2500
- B. 2400
- C. 2600
- D. 2300 Discuss
- 3. What should come in place of the question mark(?) in the following questions ? 316 + 412 - 223 - 11112 = ?
Options- A. 1 7/12
- B. 1 5/12
- C. 3 7/12
- D. 3 1/12 Discuss
- 4. A sum of Rs.1890 has to be used to give 9 prizes to the customers of a super market for their overall academic purchases. If each prize is Rs.30 less than its preceding price, what is the least value of the price ?
Options- A. 90
- B. 95
- C. 85
- D. 80 Discuss
- 5. The value of -4-(-10) is how much greater then the value of -10-(-4) ?
Options- A. 10
- B. 6
- C. 12
- D. 0 Discuss
- 6. Find the quadratic equations whose roots are the reciprocals of the roots of 2x2+5x+3 ? A) 3x2+5x+2=0 B) 5x2+3x+2=0 C) 3x2-5x-2=0 D) None
Options- A. A
- B. B
- C. C
- D. D Discuss
- 7. The last two digits of 2151415 ?
Options- A. 81
- B. 61
- C. 91
- D. 51 Discuss
- 8. Find the Value of ? 5.112.2+5.553.3+6.31.4+7.22.001 = ? x 3.34
Options- A. 81
- B. 77
- C. 73
- D. 89 Discuss
- 9. Can you Solve 7 + 7 ÷ 7 + 7 x 7 + 7 - 7 ÷ 7 + 7 x 7 =
Options- A. 112
- B. 56
- C. 0
- D. 98 Discuss
- 10. 3 x 3 + 3 - 3 + 3 = ?
Options- A. 9
- B. 12
- C. -3
- D. 3 Discuss
More questions
Correct Answer: u = 1, v = 3/2
Explanation:
Using Trial and error method,
From the options u = 1, v = 3/2 satisfies both the equations.
Correct Answer: 2400
Explanation:
Given (49.001)2 = ?
=> =~ 49 x 49
=~ 2401
=~ 2400
Correct Answer: 3 1/12
Explanation:
? = (3 + 4 - 2 - 1) + ( 1/6 + 1/2 - 2/3 - 11/12)
= 4 + [(2+6-8-11)/12]
= 4 - (11/12 )= 31/12.
Correct Answer: 90
Explanation:
Let the least value of the prize = Rs. x
Then the next value of the prize is x+30 , x+60, x+90, ....x+240.
Given total amount of cash prizes = Rs.1890
--> x + (x+30) + (x+60) + (x+90) + ....+ (x+240) = 1890
--> 9x + (30 + 60 + 90 + 120 + 150 + 180 + 210 + 240) = 1890
--> 9x + 30(1 + 2 + 3 + 4....+ 8) = 1890
--> 9x + 30(36) = 1890
--> 9x = 810 --> x=90
Hence the least value of the prize x=90
Correct Answer: 12
Explanation:
-4-(-10) = -4+10 = 6
-10-(-4) = -10+4= -6
Therefore, 6-(-6) = 6+6 = 12
Correct Answer: A
Explanation:
The quadratic equation whose roots are reciprocal of can be obtained by replacing x by 1/x.
Hence, 2(1/x)(1/x)+ 5(1/x) + 3 = 0
=>
Correct Answer: 51
Explanation:
Unit digit of this expression is always 1 as the base ends with 1.
For the tenth place digit we need to multiply the digit in the tenth place of the base and unit digit of the power and take its unit digit.
i.e, tenth place digit in 2151 is 5 and
tenth place digit in power 415 is 1
And the units digit in the product of 5 x 1 = 5
Therefore, last two digits of is 51.
Correct Answer: 89
Explanation:
This can be done in a method called Approximation.
Now,
Correct Answer: 112
Explanation:
Correct Answer: 12
Explanation:
Using BODMAS law,
3 x 3 + 3 - 3 + 3 =
3 x 3 = 12
= 12 + 3 - 3 + 3
= 9 + 3
= 12
Hence, 3 x 3 + 3 - 3 + 3 = 12.
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