Clearly, the required number would be such that it leaves a remainder of 1 when divided by 3, 4, 5, or 6 and no remainder when divided by 7. Thus, the number must be of the form (L.C.M of 3, 4, 5, 6) x + 1 i.e., (60x + 1 ) and a multiple of 7. Clearly, for x = 5, the number is a multiple of 7. So the number is 301.
the pattern is ... babc
All are rodents or rat family, except cat.
Barrow' is man-driven cart whereas others are usual.
Except option (d), all letters in pairs having difference of four.
The relationship is x : (x2 - 9).
63/3 = 21
27/3 = 9
F
Except option (c) rest all are perfect squares.
Except, `Plate', all two in number.
All other terms are used to denote the size.
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