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- Question
In three coloured boxes - Red, Green and Blue, 108 balls are placed. There are twice as many balls in the green and red boxes combined as there are in the blue box and twice as many in the blue box as there are in the red box. How many balls are there in the green box ?
Options- A. 18
- B. 36
- C. 45
- D. None of these
- Correct Answer
- None of these
ExplanationLet R, G and B represent the number of balls in red, green and blue boxes respectively.
Then,
R + G + B = 108 ...(i),
G + R = 2B ...(ii)
B = 2R ...(iii)
From (ii) and (iii), we have G + R = 2x 2R = 4R or G = 3R.
Putting G = 3R and B = 2R in (i), we get:
R + 3R + 2R = 108 => 6R = 108 => R = 18.
Therefore Number of balls in green box = G = 3R = (3 x 18) = 54.
- 1. Ayush was born two years after his father's marriage. His mother is five years younger than his father but 20 years older than Ayush who is 10 years old. At what age did the father get married ?
Options- A. 23 years
- B. 25 years
- C. 33 years
- D. 35 years Discuss
- 2. Today is Varun's birthday. One year, from today he will be twice as old as he was 12 years ago. How old is Varun today ?
Options- A. 20 years
- B. 22 years
- C. 25 years
- D. 27 years Discuss
- 3. A tailor had a number of shirt pieces to cut from a roll of fabric. He cut each roll of equal length into 10 pieces. He cut at the rate of 45 cuts a minute. How many rolls would be cut in 24 minutes ?
Options- A. 32 rolls
- B. 54 rolls
- C. 108 rolls
- D. 120 rolls Discuss
- 4. Two bus tickets from city A to B and three tickets from city A to C cost Rs. 77 but three tickets from city A to B and two tickets from city A to C cost Rs. 73. What are the fares for cities B and C from A ?
Options- A. Rs. 4, Rs. 23
- B. Rs. 13, Rs. 17
- C. Rs. 15, Rs. 14
- D. Rs. 17, Rs. 13 Discuss
- 5. If you write down all the numbers from 1 to 100, then how many times do you write 3 ?
Options- A. 11
- B. 18
- C. 20
- D. 21 Discuss
- 6. In a class of 60 students, the number of boys and girls participating in the annual sports is in the ratio 3 : 2 respectively. The number of girls not participating in the sports is 5 more than the number of boys not participating in the sports. If the number of boys participating in the sports is 15, then how many girls are there in the class ?
Options- A. 20
- B. 25
- C. 30
- D. Data inadequate Discuss
- 7. What is the product of all the numbers in the dial of a telephone ?
Options- A. 1,58,480
- B. 1,59,450
- C. 1,59,480
- D. None of these Discuss
- 8. The sum of three consecutive multiples of 3 is 72. What is the second largest number ?
Options- A. 27
- B. 24
- C. 21
- D. 42 Discuss
- 9. A, B, C, D and E play a game of cards. A says to B, "If you give me 3 cards, you will have as many as I have at this moment while if D takes 5 cards from you, he will have as many as E has." A and C together have twice as many cards as E has. B and D together also have the same number of cards as A and C taken together. If together they have 150 cards, how many cards has C got ?
Options- A. 28
- B. 29
- C. 31
- D. 35 Discuss
- 10. Ravi's brother is 3 years senior to him. His father was 28 years of age when his sister was born while his mother was 26 years of age when he was born. If his sister was 4 years of age when his brother was born, what were the ages of Ravi's father and mother respectively when his brother was born ?
Options- A. 32 years, 23 years
- B. 32 years, 29 years
- C. 35 years, 29 years
- D. 35 years, 33 years Discuss
Arithmetic Reasoning problems
Search Results
Correct Answer: 23 years
Explanation:
Ayush's present age = 10 years.
His mother's present age = (10 + 20) years = 30 years.
Ayush's father's present age = (30 + 5) years = 35 years.
Ayush's father's age at the time of Ayush's birth = (35 - 10) years = 25 years.
Therefore Ayush's father's age at the time of marriage = (25 - 2) years = 23 years.
Correct Answer: 25 years
Explanation:
Let Varun's age today = x years.
Then, Varun's age after 1 year = (x + 1) years.
Therefore x + 1 = 2 (x - 12) => x + 1 = 2x - 24 => x = 25.
Correct Answer: 120 rolls
Explanation:
Number of cuts made to cut a roll into 10 pieces = 9.
Therefore, Required number of rolls = (45 x 24)/9 = 120.
Correct Answer: Rs. 13, Rs. 17
Explanation:
Let Rs. x be the fare of city B from city A and Rs. y be the fare of city C from city A.
Then, 2x + 3y = 77 ...(i) and
3x + 2y = 73 ...(ii)
Multiplying (i) by 3 and (ii) by 2 and subtracting, we get: 5y = 85 or y = 17.
Putting y = 17 in (i), we get: x = 13.
Correct Answer: 20
Explanation:
Clearly, From 1 to 100, there are ten numbers with 3 as the unit's digit - 3, 13, 23, 33, 43, 53, 63, 73, 83, 93 and ten numbers with 3 as the ten's digit - 30, 31, 32, 33, 34, 35, 36, 37, 38, 39.
So, required number = 10 + 10 = 20.
Correct Answer: 30
Explanation:
Let the number of boys and girls participating in sports be 3x and 2x respectively.
Then, 3x = 15 or x = 5.
So, number of girls participating in sports = 2x = 10.
Number of students not participating in sports = 60 - (15 + 10) = 35.
Let number of boys not participating in sports be y.
Then, number of girls not participating in sports = (35 -y).
Therefore (35 - y) = y + 5 <=> 2y<=> 30<=> y = 15.
So, number of girls not participating in sports = (35 - 15) = 20.
Hence, total number of girls in the class = (10 + 20) = 30.
Correct Answer: None of these
Explanation:
Since one of the numbers on the dial of a telephone is zero, so the product of all the numbers on it is 0.
Correct Answer: 24
Explanation:
Let the numbers be 3x, 3x + 3 and 3x + 6.
Then,
3x + (3x + 3) + (3x + 6) = 72
9x = 63
x = 7
Largest number = 3x + 6 = 27.
=> Second largest number = 27 - 3 = 24
Correct Answer: 28
Explanation:
Clearly, we have :
A = B - 3 ...(i)
D + 5 = E ...(ii)
A+C = 2E ...(iii)
B + D = A+C = 2E ...(iv)
A+B + C + D + E=150 ...(v)
From (iii), (iv) and (v), we get: 5E = 150 or E = 30.
Putting E = 30 in (ii), we get: D = 25.
Putting E = 30 and D = 25 in (iv), we get: B = 35.
Putting B = 35 in (i), we get: A = 32.
Putting A = 32 and E = 30 in (iii), we get: C = 28.
Correct Answer: 32 years, 23 years
Explanation:
When Ravi's brother was born, let Ravi's father's age = x years and mother's age = y years.
Then, sister's age = (x - 28) years. So, x - 28 = 4 or x = 32.
Ravi's age = (y - 26) years. Age of Ravi's brother = (y - 26 + 3) years = (y - 23) years.
Now, when Ravi's brother was born, his age = 0 i.e. y - 23 = 0 or y = 23.
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