AC-AB<BC Or AB+BC>AC
BC-AC<AB Or AB+AC>BC
AB-BC<AC Or AC+BC>AB
Sum of 2 sides of triangle is always greater than the third side
So all three statements are true
Since it is an isosceles trapezium
So angle C = angle D = x
let A = 180 ?D = 180 ?x (since AB is parallel to CD)
B = 180-x
A+C = 180 ?x + x = 180 degrees (Property of cyclic quadrilateral)
ABCD is cyclic parallelogram with AB // CD and AD // BC
Considering angles A = C = y (Property of parallelogram) and B=D = x Also since it is cyclic A+C = B+D = 180 degrees
So x=y=90 degrees And also opposite sides are equal being a parallelogram
Thus ABCD is a rectangle
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