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- Question
The ratio between the length and the breadth of a rectangular park is 3 : 2. If a man cycling along the boundary of the park at the speed of 12 km/hr completes one round in 8 minutes, then the area of the park (in sq. m) is:
Options- A. 15360
- B. 153600
- C. .30720
- D. 307200
- Correct Answer
- 153600
ExplanationPerimeter = Distance covered in 8 min. = (12000/60) * 8 = 1600m
Let length = 3x metres and breadth = 2x metres.
Then, 2(3x + 2x) = 1600 or x = 160.
Length = 480 m and Breadth = 320 m.
Area = (480 x 320) = 153600
- 1. A sphere of radius 21 cm is cut into 8 identical parts by 3 cuts (1 cut along each axis). What will be the total surface area (in cm2) of each part?
Options- A. 844.5
- B. 1732.5
- C. 1039.5
- D. 1115.6 Discuss
- 2. The radius and height of a solid cylinder are increased by 2% each. What will be the approximate percentage increase in volume?
Options- A. 6.76
- B. 5.88
- C. 6.12
- D. 3.34 Discuss
- 3. A right triangular prism has equilateral triangle as its base. Side of the triangle is 15 cm. Height of the prism is 20?3 cm. What is the volume (in cm3) of the prism?
Options- A. 1125
- B. 6750
- C. 4500
- D. 3375 Discuss
- 4. ?ABC is isosceles having AB = AC and ?A = 40°. Bisectors PO and OQ of the exterior angles ?ABD and ?ACE formed by producing BC on both sides, meet at O. Then the value of ?BOC is
Options- A. 70°
- B. 110°
- C. 80°
- D. 55° Discuss
- 5. ? PQR is right angled at Q. If m?R = 60°, what is the length of PR (in cm), if RQ = 4?3 cm?
Options- A. 8
- B. 4
- C. 8/?3
- D. 8?3 Discuss
- 6. An error 2% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is:
Options- A. 2%
- B. 2.02%
- C. 4%
- D. .4.04% Discuss
- 7. The ratio between the perimeter and the breadth of a rectangle is 5 : 1. If the area of the rectangle is 216 sq. cm, what is the length of the rectangle?
Options- A. 16cm
- B. 18cm
- C. 24cm
- D. .Data inadequate Discuss
- 8. The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is:
Options- A. 1520 sq.m
- B. 2420 sq.m
- C. 2480 sq.m
- D. 2520 sq.m Discuss
- 9. The length of a rectangle is halved, while its breadth is tripled. What is the percentage change in area?
Options- A. 25% increase
- B. 50% increase
- C. 50% decrease
- D. 75% decrease Discuss
- 10. A tank is 25 m long, 12 m wide and 6 m deep. The cost of plastering its walls and bottom at 75 paise per sq. m, is:
Options- A. Rs. 456
- B. Rs. 458
- C. Rs. 558
- D. Rs. 568 Discuss
Volume and Surface Area problems
Search Results
Correct Answer: 1732.5
Correct Answer: 6.12
Correct Answer: 3375
Correct Answer: 70°
Correct Answer: 8?3
Correct Answer: .4.04%
Explanation:
100 cm is read as 102 cm.
A1 = (100 x 100) and A2 =(102 x 102)
(A2 - A1) = [(102 x 102)-(100 x 100) ]= 404
Percentage error =[404/(100 x 100 )] x 100%= 4.04%
Correct Answer: 18cm
Explanation:
2(l+b)/b = 5/1
=> 2l + 2b = 5b
=> 3b = 2l
=> b =(2/3) x l
Then, Area = 216 sq.cm
l x b = 216
=> l x [(2/3)x l] =216
=> l x l = 324
=> l = 18 cm.
Correct Answer: 2520 sq.m
Explanation:
We have: (l - b) = 23 and 2(l + b) = 206 or (l + b) = 103.
Solving the two equations, we get: l = 63 and b = 40.
Area = (l x b) = (63 x 40) sq.m
= 2520 sq.m
Correct Answer: 50% increase
Explanation:
Let original length = x and original breadth = y.
Original area = xy.
New length = x/2 and New breadth = 3y.
New area = (x/2 * 3y) = (3/2 )xy
Therefore, Increase % = [(1/2)xy * (1/xy) * 100] % = 50%
Correct Answer: Rs. 558
Explanation:
Area to be plastered= [2(l + b) x h] + (l x b)
= [2(25 + 12) x 6] + (25 x 12)
= (444 + 300)
= 744
Cost of plastering = Rs. 744 x (75/100)= Rs. 558
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