The century divisible by 400 is a leap year. 2100 is not divisible by 400 hence is not a leap year.
? Cost of 6 dozen chairs = 6 x 12 x214 = Rs. 15408
And cost of 4 dozen tables = 4 x 12 x 937 = Rs. 44976
? Total cost =15408 + 44976
= Rs. 60384
= Rs. 60000 (Approximately)
? = 783/9 x 0.75 = 116
724 ÷ 25 x 31.05 + 101 = ?
? ? = 725 ÷ 25 x 31 + 101
= 29 x 31+ 101
= 899 + 101 = 1000
Speed of train in m/sec = (speed of train in km/hr) x 5/18
? speed of train in m/sec = 54 x 5/18 = 15 m/sec
Time taken to cross the tunnel = 2 minutes = 120 sec
Therefore, Total length covered by train in crossing the tunnel = Speed of train x Time taken to cross the tunnel
= 15 m/sec x 120 sec = 1800 m
Now, we know that
Total length covered by train in crossing the tunnel = Length of train + Length of tunnel
Given, Length of train =400m and
Calculated above, Length covered by train in crossing the tunnel = 1800 m
Therefore, Length of tunnel = 1800m- 400m = 1400m
If the two alloys are mixed, the mixture would contain 15 gms of each metal and it would cost Rs. (150 + 120) = Rs. 270.
Cost of (15 gms of metal A + 15 gms of metal B) = Rs. 270
Cost of (1 gm of metal A + 1 gm of metal B) = Rs. (270 / 15) = Rs. 18
Cost of 1 gm of metal B = Rs. (18 ? 6) = Rs. 12
Average cost of original piece of alloy = (150 / 15) = Rs. 10 per gm.
Quantity of metal / A Quantity of metal B = (2 / 4) = (1 / 2)
Quantity of metal B = 2 (1 + 2) × 15 = 10 gms.
Speed = | ❨ | 600 | ❩m/sec. |
5 x 60 |
= 2 m/sec.
Converting m/sec to km/hr (see important formulas section)
= | ❨ | 2 x | 18 | ❩ | km/hr |
5 |
= 7.2 km/hr.
According to the question, A : B = 200 : 150
and B : C = 200 : 192
? A : C = (A/B) x (B/C) = (200/150) x (200/192) = 200/144
So, A beats C by (200 - 177) = 56 m
26.823 x 27.923 x 4.5001
? 27 x 28 x 4.5000 = 756 x 4.5000 = 3402 ? 3400
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